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3 years ago

Can anyone help check if my calculation is correct or wrong?

Mathematics

2 answers:

8_murik_8 [283]3 years ago

6 0

It’s correct good job

BigorU [14]3 years ago

5 0

You are correct dude

You might be interested in

Which mark on the tape measure is closest to 2.23607 inches?

Lapatulllka [165]

Answer:

5.7 cm or 2 1/4 in

Step-by-step explanation:

Your tape measure is not shown.

On my tape measure, 5.7 cm is the closest mark. On the inch scale, 2 1/4 inches is the next-closest mark.

_____

On a tape measure graduated in 1/32 inch between 2 and 3 inches, you can find the closest mark by rounding to the nearest 32nd:

2.23607 × 32 ≈ 71.55 ≈ 72 --- 32nds of an inch

72/32 = 2 1/4 . . . . the closest mark on an inch ruler graduated in 32nds

For a ruler graduated in millimeters, you can find the closest millimeter in the same way. There are 25.4 mm to the inch.

2.23607 in × 25.4 mm/in ≈ 56.80 mm ≈ 57 mm

57 mm = 5.7 cm . . . closest mark on metric scale

When we check the error, we find the metric mark is closer than the inch mark.

5.7 cm ≈ 2.24409 in . . . . error of 0.00802 in

2 1/2 in = 2.25000 in . . . error of 0.01393 in

5 0

3 years ago

HELP ME PLSSSSS I NEED HELP PLS PLS PLS ITS PYTHAGOREAN THEOREM

sergij07 [2.7K]

H=9ft
B=6ft

Using Pythagorean thereon

$\\ \Large\sf\longmapsto P^2=H^2-B^2$

$\\ \Large\sf\longmapsto P^2=9^2-6^2$

$\\ \Large\sf\longmapsto P^2=81-36$

$\\ \Large\sf\longmapsto P^2=45$

$\\ \Large\sf\longmapsto P=\sqrt{45}$

$\\ \Large\sf\longmapsto P=6.3ft$

7 0

2 years ago

The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff. What is the init

Gwar [14]

Did you ever get this answer?? I really need it

4 0

3 years ago

Read 2 more answers

A rock dropped on the moon will increase its speed from 0 m/s (its starting

belka [17]

<h2>Hello!</h2>

The answer is:

The correct option is the option D

$g=1.63\frac{m}{s^{2}}$

To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).

We need to use the following free fall equation:

$V_{f}=V_{o}-g*t$

Where:

$V_{f}$ is the final speed.

$V_{o}$ is the initial speed.

g is the acceleration due to gravity.

t is the time.

We are given the following information:

$V_{f}=8.15\frac{m}{s}$

$V_{o}=0\frac{m}{s}$

$t=5seconds$

Then, using the formula to isolate the acceleration, we have:

$V_{f}=V_{o}-g*t$

$V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}$

Now, substituting we have:

$g=\frac{V_{o}-V_{f}}{t}$

$g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}$

Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:

$g=1.63\frac{m}{s^{2}}$

Hence, the correct option is the option D

$g=1.63\frac{m}{s^{2}}$

Have a nice day!

7 0

3 years ago

Solve the area formula for h

White raven [17]

The answer is C: $h = \frac{2A}{b}$

Starting with the given formula for the area, A = 1/2hb, the first step is to isolate h by using the multiplicative inverse of b, which is $\frac{1}{b}$ on both sides of the equation:

$A(\frac{1}{b}) = \frac{1}{2}hb* (\frac{1}{b})$

The result will be:

$\frac{A}{b} = \frac{1}{2}h$

The last step is to use the multiplicative inverse of $\frac{1}{2}$ , which is 2 or $\frac{2}{1}$ to further isolate the variable <em>h </em>:

$\frac{A}{b} (\frac{2}{1}) = (\frac{2}{1}) \frac{1}{2} h$

The formula for h will be:

$h = \frac{2A}{b}$ which is the option C in your question.

4 0

3 years ago