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2 years ago

Angles A and B are supplementary. Angle A has a measure of 80°. What is the measure of angle B?

Mathematics

2 answers:

zheka24 [161]2 years ago

6 0

Answer:

100

Step-by-step explanation:

I just took the test

olganol [36]2 years ago

5 0

Supplementary angles: sum of the angles measure to be 180º
180º-A= B
Plug in...
180º-80º= 100º

So, angle B must be 100 degrees.

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When e = 4, f = 2, and g = 8If e varies jointly with f and g, what is the constant of variation?

tatyana61 [14]

Answer:

$e=\frac{1}{4} fg$

Step-by-step explanation:

Joint variation problem solve using the equation y = kxz.

e ∝ fg

e=kfg

now substitute the values

$4=k*2*8\\4=16k\\k=\frac{4}{16} \\k=\frac{1}{4}$

The relationship will be:

$e=kfg\\e=\frac{1}{4} fg$

8 0

2 years ago

Read 2 more answers

muhammad, a shipping and receiving clerk uses 1 yard, 2 feet and 4 inches Of twine to wrap each carton he packs. he has to pack

antiseptic1488 [7]

Answer:

He will need 51 yards, 1 foot and 8 inches twine to wrap 29 cartons.

Step-by-step explanation:

Muhammad uses 1 yard, 2 feet and 4 inches of twine to wrap each carton he packs.

We know that, 1 yard = 36 inches and 1 foot = 12 inches.

So, 1 yard, 2 feet and 4 inches $=[(1*36)+(2*12)+4]inches = 64$ inches.

That means, he uses 64 inches of twine to wrap each carton.

He has to pack 29 cartons today. So, the total length of the twine he will need $=(64*29) inches= 1856$ inches.

Now....

1856 inches

$=\frac{1856}{36} yards \\ \\= 51 \frac{5}{9} yards \\ \\= 51 yards+(\frac{5}{9}*36)inches \\ \\= 51 yards, 20 inches \\ \\= 51 yards, (12+8)inches \\ \\=51 yards, 1 foot, 8 inches.$

Thus, he will need 51 yards, 1 foot and 8 inches twine to wrap 29 cartons.

8 0

3 years ago

What is the fractional equivalent of 225%?

vitfil [10]

You would start out by putting 225 over 100 then simplifying from there. You would end up getting 9/4. As a mixed number that would be 2 and 1/4.

7 0

2 years ago

Read 2 more answers

Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

zloy xaker [14]

Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.

7 0

3 years ago

ANSWER FAST MY DUDEZ! What is the value of x in the equation 1.8- 3.7x = 4.2x + 0.3

Inessa [10]

1.8- 3.7x = 4.2x + 0.3

Move 4.2x to the other side

Sign changes from +4.2x to -4.2x

1.8-3.7x-4.2x= 4.2x-4.2x+0.3

1.8-3.7x-4.2x= 0.3

1.8-7.9x= 0.3

Move 1.8 to the other side

Sign changes from +1.8 to -1.8

1.8-1.8-7.9x= 0.3-1.8

-7.9x= 0.3-1.8

-7.9x= -1.5

divide both sides by -7.9

-7.9/-7.9x= -1.5/-7.9

x= 0.18987341

Answer: x= 0.18987341

8 0

3 years ago