Ask question

Ask question

All categories

3 years ago

10

After buying some new coins, Andre has 80 coins in his collection. Last month, he had 50 coins. The size of his current collecti

on is what percentage of his collection last month?

1 answer:

marta [7]3 years ago

5 0

Answer:

160%

Step-by-step explanation:

You might be interested in

Need help ASAP thank you

Sedaia [141]

The height of the barrel is 6 feet.

3 0

3 years ago

Identify the rule for the following pattern: <br> 4, 24, 144

Ivan

Answer:

It is being multiplied by 6 each time.

Step-by-step explanation:4x6, 24x6

7 0

3 years ago

Given two vectors A=2i+3j+4k,B=i-2j+3k find the magnitude and direction of sum<br>(physics question)

Law Incorporation [45]

Answer:

$Magnitude =\sqrt{59} \\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}}$

Step-by-step explanation:

A=2i+3j+4k

B=i-2j+3k

Sum of the vectors:

A + B = 2i+3j+4k + i-2j+3k = 3i + j + 7k

$Magnitude =\sqrt{3^2 + 1^2+ 7^2} \\\\Magnitude =\sqrt{9+1+49} \\\\Magnitude =\sqrt{59}$

Direction of the sum of the vectors:

$\widehat{A + B} =\frac{\overrightarrow{A + B}}{Magnitude\: of \:\overrightarrow{A + B}} \\\\\widehat{A + B} =\frac{3i + j + 7k}{\sqrt {59}} \\\\\widehat{A + B} =\frac{3}{\sqrt {59}} i +\frac{1}{\sqrt {59}} j+\frac{7}{\sqrt {59}} k\\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}} \\\\$

3 0

2 years ago

Factor. 2x2−3x−5 (2x+5)(x−1) (x−5)(2x+1) (2x−5)(x−1) (2x−5)(x+1)

Likurg_2 [28]

Answer:

0

Step-by-step explanation

You do the brackets first
The answer to the brackets is : 0
Because you also times the others by 0 the answer must be 0.

7 0

3 years ago

Read 2 more answers

Jacob and Ali want to run from one corner of a football field to the opposite corner. The rectangular football field is 50 yards

svet-max [94.6K]

Answer:

Jacob ran 40 yards more than Ali.

Step-by-step explanation:

Football field is in the shape of a rectangle having dimensions 120 yards × 50 yards

Since Jacob runs around the perimeter of the field from one corner to other corner, therefore, distance run by Jacob = $(\text{Length+width})$

Distance run by Jacob = 50 + 120 = 170 yards

Ali runs through the middle of the field diagonally on a straight line.

Therefore, distance covered by Ali = $\sqrt{\text{length}^{2}+\text{width}^{2}}$

= $\sqrt{(50)^{2}+(120)^{2}}$

= $\sqrt{2500+14400}$

= $\sqrt{16900}$

= 130 yards

Now difference between the distance covered by Jacob and Ali

= 170 - 130

= 40 yards

Therefore, Jacob ran 40 yards more than Ali.

7 0

3 years ago