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Svet_ta [14]
3 years ago
9

Question 3 Write the rational number as a decimal.

Mathematics
2 answers:
Aneli [31]3 years ago
7 0

Answer: -2.2

Step-by-step explanation:

-10 is the most possible that can be divided by 5, resulting in -2.

The leftover 1 is divided by 5, resulting in .2.

The decimal ends up being -2.2.

allsm [11]3 years ago
3 0

Answer:

-2.2 or -1.2

Step-by-step explanation:

When you want to write a decimal as a fraction, you simply divide the numerator with the denominator. So when you divide -11 by five that would be a -2.2. Or if it is -1 1/5 the answer would be -1.2. I cant really tell what that number is.

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Find the equation of the line with the given properties: passes<br> through (2,3) and (2,9).
Rama09 [41]

Answer: x=2

both 3 and 9 share the same x axis

8 0
3 years ago
Please help it's in math
goldenfox [79]

Answer:

Step-by-step explanation:

area of front face=(12+8)/2 ×8=80 cm²

volume=80×22=1760 cm³

8 0
4 years ago
Here is a triangle with the height on the side of the triangle. Use the formula: (1/2)*(Base)*(Height) to find the area of the t
jasenka [17]

<em>(If one square on the graph = one centimeter)</em>

<u>b = 10cm</u>

<u>b = 10cmh = 10cm</u>

Area:

=  \frac{1}{2}  \times b \times \: h

=  \frac{1}{2 }  \times 10 \times 10

=  \frac{1}{2}  \times 100

= 50 {cm}^{2}

3 0
3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.
Tema [17]

Answer:

Area  \approx 1149\ cm^2

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to \angle W)

Side u = 83 cm (It is the side opposite to \angle U)

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

A = \dfrac{1}{2}\times a\times b\times sinC

Where a and b are the two sides and

\angle C is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A  \approx 1149\ cm^2

So, the <em>area </em>of given triangle to the nearest square centimetre is:

Area  \approx 1149\ cm^2

8 0
4 years ago
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