Question

Function Operations Picture attached

Answer 1

Answer: Second option

Step-by-step explanation:

You need to make the multiplication of the function $c(x)=\frac{5}{x-2}$ and the function $d(x)=x+3$. Then:

$(cd)(x)=(\frac{5}{x-2})(x+3)$

You need to apply the Distributive property:

$(cd)(x)=\frac{5(x+3)}{x-2}\\\\(cd)(x)=\frac{5x+15}{x-2}$

Therefore, the domain will be all the number that make the denominator equal to zero.

Then, make the denominator equal to zero and solve for x:

$x-2=0\\x=2$

Therefore, the domain is: All real values of x except $x=2$