You will go 495 miles in 9 hours
Broken yellow b/c you can’t pass on a double solid yellow
Answer:
V=1601gal
Explanation:
Hello! This problem is solved as follows,
First we must raise the equation that defines the pressure at the bottom of the tank with the purpose of finding the height that olive oil reaches.
This is given as the sum due to the atmospheric pressure (1atm = 101.325kPa), and the pressure due to the weight of the olive oil, taking into account the above, the following equation is inferred.
P=Poil+Patm
P=total pressure or absolute pressure=26psi=179213.28Pa
Patm= the atmospheric pressure =101325Pa
Poil=pressure due to the weight of olive oil=0.86αgh
α=density of water=1000kg/m^3
g=gravity=9.81m/s^2
h= height that olive oil reaches
solving
P=Poil+Patm
P=Patm+0.86αgh
[/tex]
Now we can use the equation that defines the volume of a cylinder.
V=![V=\frac{\pi }{4} D^{2} h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20D%5E%7B2%7D%20h)
D=3ft=0.9144m
h=9.23m
solving
![V=\frac{\pi }{4} (0.9144)^{2} 9.23=6.06m^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%280.9144%29%5E%7B2%7D%209.23%3D6.06m%5E3)
finally we use conversion factors to find the volume in gallons
![V=6.06m^3\frac{1000L}{1m^3} \frac{1gal}{3.785L} =1601gal](https://tex.z-dn.net/?f=V%3D6.06m%5E3%5Cfrac%7B1000L%7D%7B1m%5E3%7D%20%5Cfrac%7B1gal%7D%7B3.785L%7D%20%3D1601gal)
Answer:
hello some part of your question is missing below is the complete question
answer :
A) 162750 Ib.ft
B) - 64950 Ib.ft
Explanation:
Applying Muller-Breslau's law
we will make assumptions which include assuming an imaginary hinge at G
therefore the height of I.LD for B.M at G = ( 12 * 8 ) / 20 = 4.8
height of I.L.D at C = 2.4 ( calculated )
height of I.L.D at F = 1.5 ( calculated )
A) Determine Maximum positive moment produced at G
= [ (1/2 * 20 * 4.8 ) ( 600 + 300 ) ] + [ ( 25 * 4.8 * 10^3 ) ] - [ ( 1/2 *2.4*20 ) * 300 ] + [ (1/2 * 1.5 * 10 ) ( 600 + 300 ) ]
= 162750 Ib.ft
B) Determine the maximum negative moment produced at G
= [ ( 1/2 * 20 * 4.8 ) * 300 ] - [ ( 1/2 * 2.4 * 20 ) ( 600 + 300 ) ] - [ (2.5 * 10^3 * 2.4 ) ] + [ ( 1/2 * 1.5 * 10) * 300 ]
= - 64950 Ib.ft