Answer: C) a&c
Explanation: Composite materials are the materials which are made up of the two or more material of different properties.They are usually having properties like high hardness,low in density,no dissolving into each other etc. Whiskers as a dispersing agent in composite materials are usually not preferred because they are expensive as well as they are not easy to disperse in the composite material.Thus option (c) is the correct answer.
Answer:
Hold the tape in place and go down to the end.
Explanation:
Answer:
Given
inlet Pga =40kpa = 40000pa
Patm=1.01bar = 1.01 x 100000pa =101000pa
exit Pab= 6.5 (inlet Pab)
But generally, Pab = Patm + Pga
1. the absolute pressure of the gas at the inlet, inlet Pab?
inlet Pab = Patm + inlet Pga
= 101000pa + 40000pa = 141kpa
the absolute pressure of the gas at the inlet, inlet Pab = 141kpa
2. the gage pressure of the gas at the exit? exit Pga?
exit Pab = Patm + exit Pga
exit Pga = exit Pab - Patm
= (6.5 x 141kpa) - 101kpa
= 815.5kpa
the gage pressure of the gas at the exit exit Pga=815.5kpa
Answer:
P = 4.745 kips
Explanation:
Given
ΔL = 0.01 in
E = 29000 KSI
D = 1/2 in
LAB = LAC = L = 12 in
We get the area as follows
A = π*D²/4 = π*(1/2 in)²/4 = (π/16) in²
Then we use the formula
ΔL = P*L/(A*E)
For AB:
ΔL(AB) = PAB*L/(A*E) = PAB*12 in/((π/16) in²*29*10⁶ PSI)
⇒ ΔL(AB) = (2.107*10⁻⁶ in/lbf)*PAB
For AC:
ΔL(AC) = PAC*L/(A*E) = PAC*12 in/((π/16) in²*29*10⁶ PSI)
⇒ ΔL(AC) = (2.107*10⁻⁶ in/lbf)*PAC
Now, we use the condition
ΔL = ΔL(AB)ₓ + ΔL(AC)ₓ = ΔL(AB)*Cos 30° + ΔL(AC)*Cos 30° = 0.01 in
⇒ ΔL = (2.107*10⁻⁶ in/lbf)*PAB*Cos 30°+(2.107*10⁻⁶ in/lbf)*PAC*Cos 30°= 0.01 in
Knowing that PAB*Cos 30°+PAC*Cos 30° = P
we have
(2.107*10⁻⁶ in/lbf)*P = 0.01 in
⇒ P = 4745.11 lb = 4.745 kips
The pic shown can help to understand the question.