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Zina [86]
3 years ago
8

I NEED HELP ASAP WILL AWARD BRAINLIEST

Engineering
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer:

It was a power supply of a circuit that was horizontal of the ladder where they controlled the circuit.

Explanation:

quester [9]3 years ago
3 0
Going CLOCKWISE starting from the LARGEST component: charge (in this case, it’s the battery), switch (that thing is literally called a switch), load (in this case, it’s a light bulb), wire (it’s literally called a wire) i hope that helps!!
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Answer:

BDEG

Explanation:

got it right on the test on edge because i used my b r a i n

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W10L1-Show It: Pythagorean Theorem<br> Calculate the total material in the picture.<br> 4<br> 3
Fantom [35]

Answer:

35

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4. What are these parts commonly called?
patriot [66]

These parts are commonly called carburetor emulsion tubes. These tubes maintain the air-fuel ratio at different speeds.

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7 0
3 years ago
What are the well-known effects of electricity​
Sever21 [200]

Answer:

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3 0
3 years ago
Read 2 more answers
1. A team of students have designed a battery-powered cooler, which promises to keep beverages at a high-drinkability temperatur
Anit [1.1K]

Answer:

Minimum electrical power required = 3.784 Watts

Minimum battery size needed = 3.03 Amp-hr

Explanation:

Temperature of the beverages, T_L = 36^0 F = 275.372 K

Outside temperature, T_H = 100^0F = 310.928 K

rate of insulation, Q = 100 Btu/h

To get the minimum electrical power required, use the relation below:

\frac{T_L}{T_H - T_L} = \frac{Q}{W} \\W = \frac{Q(T_H - T_L)}{T_L}\\W = \frac{100(310.928 - 275.372)}{275.372}\\W = 12.91 Btu/h\\1 Btu/h = 0.293071 W\\W = 12.91 * 0.293071\\W_{min} = 3.784 Watt

V = 5 V

Power = IV

W_{min} = I_{min} V\\3.784 = 5I_{min}\\I_{min} = \frac{3.784}{5} \\I_{min} = 0.7568 A

If the cooler is supposed to work for 4 hours, t = 4 hours

I_{min} = 0.7568 * 4\\I_{min} = 3.03 Amp-hr

Minimum battery size needed = 3.03 Amp-hr

6 0
3 years ago
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