10 4/10 or 10 2/5 if you reduce it
Answer:
one triangle
Step-by-step explanation:
hope this helps
Answer:
5÷A and A÷5=A×A and 5×5=A=25
Answer:
The area of the copper circle is <u>31.4 inches</u>.
Step-by-step explanation:
Given:
An artist used silver wire to make a square that has a perimeter of 40 inches.
She then used copper wire to make the largest circle that could fit in the square, with perimeter of 40 inches.
Use 3.14 to represent π.
Now, to find the area of the copper circle.
Perimeter of square = 40 inches.
So, we get the side of square by putting formula:
Dividing both sides by 4 we get:
Now, as the side of square is 10 inches it is the diameter of the circle as the square is fit inside the circle:
For getting the area of circle we find the radius:
Radius (r) = 
Now, putting the formula to get the area of the circle:
Therefore, the area of the copper circle is 31.4 inches.
The solutions to the given quadratic equation {49n² - 301n + 42 = 0 } are 1/7 and 6.
<h3>What are the solutions to the given quadratic equation?</h3>
Quadratic equation is simply an algebraic expression of the second degree in x. Quadratic equation in its standard form is expressed as;
ax² + bx + c = 0
Where x is the unknown
To solve for x, we use the quadratic formula
x = (-b±√(b² - 4ac)) / (2a)
Given the equation in the question;
49n² - 301n + 42 = 0
Compared to the standard form of quadratic equation { ax² + bx + c = 0 }
We plug in these values into the quadratic formula.
x = (-b±√(b² - 4ac)) / (2a)
x = (-(-301) ±√((-301)² - 4 × 49 × 42 )) / (2 × 49)
x = ( 301 ±√( 90601 - 8232 )) / 98
x = ( 301 ±√( 82369 )) / 98
x = ( 301 ± 287) / 98
x = (301 - 287)/98, (301 + 287)/98
x = 14/98, 588/98
x = 1/7, 6
Therefore, the solutions to the given quadratic equation {49n² - 301n + 42 = 0 } are 1/7 and 6.
Learn more about quadratic equations here: brainly.com/question/1863222
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