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3 years ago

What do you look for when solving name word problem

Mathematics

1 answer:

Alexxx [7]3 years ago

7 0

The main numbers and ratios or rates depending on the problem

You might be interested in

Find the associated reflex angle measure for an angle of 60°

sergij07 [2.7K]

The reflex angle is the other angle
see image below

so
reflex=360-angle
reflex=360-60=300
reflex angle=300

8 0

3 years ago

You and a friend are baking cookies. You ask how much water she added to the batter and she says "15" What is wrong with her ans

REY [17]

Nothing is writing with her answer

8 0

3 years ago

Read 2 more answers

Kelly has a recipe for muffins that asks for 1 1/2 cups of sugar. She wants to use half that amount of sugar. How much sugar wil

olga nikolaevna [1]

answer:

3/4 cups of sugar

Explanation:

turn 1 1/2 into a number which is 1.5 divide that by 2 which is .75 now turn that into a fraction and you get the answer 3/4 cups of sugar

7 0

3 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

3 years ago

Find the 12th term of the arithmetic sequence 2x + 8,6x + 5, 10x + 2, ...

lawyer [7]

Answer: The 12th term is 46x -25

Step-by-step explanation:

It is increasing by 4x and decreasing by 3 through each term, this represents the d. a1 has already been identified as 2x +8, so you just have to write down the formula and the solve form there by plugging in the 12 in (n-1) to find the answer.

8 0

2 years ago