Answer:To calculate this you just have to calculate a rule of three with both gas tanks, so if the dad´s car holds 12 gallons of gas, and the mom´s car holds 50% more that means 150% of in the rule of three: So the total amount of gallons that the mom´s car tank can hold is 18 gallons.
Step-by-step explanation:Please make me brainliest please
<span>If the sum of two of the sides congruent to each other are greater than that of the sides opposite them, then no. If however the kite forms a rombus ot square, the diagnoles will form four congruent triangles with the base of both being the line of symmetry.
hope this helps :)</span>
Answer:
15
Step-by-step explanation:
The difference between consecutive integers is 1.
The difference between consecutive odd integers is 2.
Let the smallest odd integer be x.
Then the next greater one is x + 2. The greatest one is x + 4.
"3 times the first" is 3x
"twice the third" is 2(x + 4)
"3 times the first of three consecutive odd integers is 3 more than twice the third"
3x = 2(x + 4) + 3
3x = 2x + 8 + 3
x = 11
The smallest integer is 11.
x + 4 = 11 + 4 = 15
The greatest one is 15.
Answer: 
Step-by-step explanation:
Given: The total number of ways of to choose 3 contestants out of 7 (including me and my friend)=35..................> Total outcomes.
Favorable outcomes = 2
Then the probability that me and my friend are both chosen =
Thus , the probability that me and my friend are both chosen =
Answer:
Step-by-step explanation:
11) First write in decreasing exponential terms and fill in blanks with zeros.
Our goal is to eliminate all term in the dividend by subtraction
________________
2v - 2 | 2v³ - 16v² + 0v + 13
we see that 2v needs to be multiplied by 1v² to eliminate the first term
<u> v² </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v²
multiply your estimate by your divisor and subtract from the dividend.
bring down the next term and repeat.
<u> v² -7v </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v² + 0v
<u>-(-14v² + 14v)</u>
- 14v
repeat again
<u />
<u> v² - 7v - 7 </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v² + 0v
<u>-(-14v² + 14v)</u>
- 14v + 13
<u>-(-14v + 14)</u>
-1
and remainder gets put over the divisor and appended
v² - 7v - 7 - 1/(2v - 2)
13) Same process
<u> </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u> 8a² </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
<u> 8a² - 4a </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
-(-<u>20a² - 4a)</u>
-35a - 5
<u> 8a² - 4a - 7 </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
-(<u>20a² - 4a)</u>
-35a - 5
-<u>(-35a - 7)</u>
2
8a² - 4a - 7 + 2/(5a + 1)
