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Rashid [163]
3 years ago
9

Factorise 80a^3-5ab2​

Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Step-by-step explanation:

Please see difference in both the answers

I am confused what is the question...

that's why....

hope it helps

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Find the theoretical probability of rolling a number cube labeled 1-12 and<br> it landing on 7.
Rashid [163]

Answer:

1/12

Step-by-step explanation:

There are 12 sides, and 7 is one of them. Therefore, there is a 1/12 chance of it landing on that side if it is a fair cube.

3 0
3 years ago
In a busy period you are required to use the support
Alex

Answer:

what are the details

Step-by-step explanation:

5 0
4 years ago
A rectangle is placed around a semicircle as shown below. The length of the rectangle is 8 cm. Find the area of the shaded regio
icang [17]

Answer:

Area of the shaded region = 6.88 cm²

Step-by-step explanation:

Area of the shaded region = Area of the rectangle - Area of the semicircle

Area of the rectangle = Length × Width

Length of the rectangle = AD = 8 cm

Width of the rectangle = OP = 4 cm [OP, OB and OC are the radii of the circle which are equal in measures]

Area of the rectangle = 8 × 4 = 32 cm²

Area of the semicircle = \frac{1}{2}\pi r^{2}

                                     = \frac{1}{2}\pi (OP)^{2}

                                     = \frac{1}{2}\pi (4)^{2}

                                     = 25.12 cm²

Area of the shaded region = 32 - 25.12

                                              = 6.88 cm²

3 0
3 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
Estimated m 60=4m <br><br><br><br><br> 4x0=
11111nata11111 [884]

[ Answer ]


M = <em><u>15</u></em>

4 * 0 = <u><em>0</em></u>

[ Explanation ]


60 / 4 = 15

15 * 4 = 60



4 * 0 = 0


<> Eclipsed <>


4 0
3 years ago
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