Correct question is;
A football is kicked up into the air. Its height, H, above the ground, in meters, at t seconds can be modelled by () = 24 − 4.9²
(a) Determine the expression for the instantaneous rate of change in height at time t.
(b) Determine ' (2) What does ' (2) represent?
Answer:
A) '() = 24 − 9.8
B) '(2) = 4.4 m/s
It means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s
Step-by-step explanation:
We are given the function to represent the height as;
() = 24 − 4.9²
A) expression for the instantaneous rate of change in height at time t will be gotten by differentiation of the height function. Thus;
'() = 24 − 9.8
B) '(2) = 24 - 9.8(2)
'(2) = 4.4 m/s
This means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s
The heat released or absorbed by a substance is calculated through the equation,
H = mcpdT
where H is teh heat,
m is the mass,
Cp is the specific heat, and
dT is the temperature difference
In this item, since both nails are identical, m and cp for both nails are equal such that the equation can be expressed as,
mcp(95 - x) = mcp(x - 15)
where x is the final temperature. Solving for the value of x from the equation derived above will give us a final answer of 55 degrees C.
Answer: 55°
8v + 8b = 240
4v + b = 54....multiply by -2
-------------------
8v + 8b = 240
-8v - 2b = - 108 (result of multiplying by -2)
------------------add
6b = 132
b = 132/6
b = 22 <== buses hold 22 students
4v + b = 54
4v + 22 = 54
4v = 54 - 22
4v = 32
v = 32/4
v = 8 <== vans hold 8 students
C, because 7 divided, or over nine, is 7/9
Hope this helps!
Given:
mean, μ = 11 lb
Std. deviation, σ = 2.1
Let x = the weight that separates the top 5% of the crop.
The z-score is
z = (x - μ)/σ
= (x - 11)/2.1
From standard z-table for normal distribution,
P(z=1.645) = 0.95
Therefore
(x - 11)/2.1 = 1.645
x - 11 = 1.645/2.1 = 0.7833
x = 11.783
Answer: 11.8 lb (nearest tenth)
