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ozzi
3 years ago
12

PrimeFactorization.java: Write a program that begins by reading in a series of positive integers on a single line of input and t

hen computes and prints the product of those integers. Integers are accepted and multiplied until the user enters an integer less than 1. This final number is not part of the product. Then, the program prints the product. If the first entered number is negative or 0, the program must print "Bad input." and terminate immediately. Next, the program determines and prints the prime factorization of the product, listing the factors in increasing order. If a prime number is not a factor of the product, then it must not appear in the factorization. Multiple sample runs are given below. Note that if the power of a prime is 1, then that 1 must appear in the answer. Note: Your program’s prompt and output messages must conform to the following spelling and spacing. - Sample Run 1: Enter integers: 882 18 26 -45 Product: 412776 Prime factorization: 2ˆ3 3ˆ4 7ˆ2 13ˆ1 - Sample Run 2: Enter integers: 19 -5 Product: 19 Prime factorization: 19ˆ1 - Sample Run 3: Enter integers: -37 99 124 22 -65
Computers and Technology
1 answer:
Mkey [24]3 years ago
3 0

Answer:

See attached file for detailed code.

Explanation:

See attached file.

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Write the definition of a function divide that takes four arguments and returns no value . The first two arguments are of type i
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Answer:

#include <iostream>

using namespace std;

void divide(int numerator, int denominator, int *quotient, int *remainder)

{

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int main()

{

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divide(num, den, &quotient, &remainder);

 

return 0;

}

Explanation:

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To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.

Thanks! :)

8 0
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Andre45 [30]

Answer:

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Explanation:

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double average =  (a + b) / 2;

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return 0;

}

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