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mario62 [17]
3 years ago
14

The quotient of a number and -7 decreased by 2, is 10.

Mathematics
1 answer:
klasskru [66]3 years ago
3 0
Hello!

This expression can be broken down into 3 separate parts:

1. "the quotient of a number and (-7)"
2. "decreased by 2"
3. "is 10"

We'll begin with the first part. The word "quotient" implies the result of a division problem. Therefore, this part can be represented by the following expression (let "x" represent the unknown number):

\frac{x}{(-7)}

Now we'll move on to the second part. If something is decreased by a value of 2, we know that 2 is being subtracted. Therefore, this part can be represented by the following expression:

– 2

Now we'll move on to the third and final part. The phrase "is 10" implies that the operations preceding this part are equal to 10. Therefore, this part can be represented by the following expression:

= 10

Finally, put the three parts together to create the following equation:

\frac{x}{(-7)} – 2 = 10

The equation has now been fully translated. If, however, you are required to find the unknown value (x), begin by adding 2 to both sides of the equation:

\frac{x}{(-7)} = 12

Now multiply both sides by (-7):

x = (-84)

We have now proven that the unknown number is equal to (-84).

I hope this helps!
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Answer:

A

Step-by-step explanation:

49y² - x² ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

49y² - x²

= (7y)² - x²

= (7y - x )(7y + x) → A

3 0
2 years ago
HELP DUE in 20 MIN<br> m∠16 =
Ierofanga [76]

9514 1404 393

Answer:

  ∠16 = 47°

Step-by-step explanation:

Vertical and corresponding angles are congruent. The remainder are supplementary to those.

∠1≅∠4≅∠5≅∠7≅∠10≅∠12≅∠13≅∠15 = 133°

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8 0
3 years ago
Determine whether each scale factor produces an expansion or a contraction under a dilation of the original image
blondinia [14]

Answer:

see the explanation

Step-by-step explanation:

we know that

If the absolute value of the scale factor is less than 1, then the dilation produces a contraction of the original image

If the absolute value of the scale factor is greater than 1, then the dilation produces an expansion of the original image

so

<u><em>Verify each value</em></u>

1) -4

\left|-4\right|=4

4> 1

therefore

The dilation produces an expansion of the original image

2) 0.25

\left|0.25\right|=0.25

0.25 < 1

therefore

The dilation produces a contraction of the original image

3) -2/3

\left|-2/3\right|=2/3

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therefore

The dilation produces a contraction of the original image

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\left|2.3\right|=2.3

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3 years ago
Can someone solve this for me please?
Ksivusya [100]
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5 0
4 years ago
Calculate the expected value, the variance, and the standard deviation of the given random variable X. (Round all answers to two
Tom [10]

Answer:

E (X) = 1.8

Var (X) = 0.36

σ = 0.6

Step-by-step explanation:

Solution:-

- Denote the random variable X : is the number of red marbles that Suzan has in her hand after she selects three marbles.

- Total sample space (bag) have the following quantity of colored marbles:

                Bag : { 3 Red , 2 Green }

- Suzan selects three marbles from the bag. The Event (X) defines the number of red marbles out of 3.

- The total number of outcomes / selections for randomly selecting 3 balls from the bag:

               All outcomes = 5 C 3 = 10

- The probability distribution of the random variable X, we will use combinations to determine the required probabilities:

  X = 1 red marble:

        P ( X = 1 ) : Suzan chooses 1 Red marble from the available 3 red marble and 2 green marbles.

        P ( X = 1 ) = [ 3C1*2C2 ] / all outcomes = (3*1) / 10 = 0.3

X = 2 red marble:

        P ( X = 2 ) : Suzan chooses 2 Red marble from the available 3 red marble and 1 green marbles.

        P ( X = 2 ) = [ 3C2*2C1 ] / all outcomes = (3*2) / 10 = 0.6

X = 3 red marble:

        P ( X = 3 ) : Suzan chooses 3 Red marble from the available 3 red marble.

        P ( X = 3 ) = [ 3C3] / all outcomes = (1) / 10 = 0.1

- The probability distribution is as follows:

          X :         1                 2                3

       P (X):       0.3            0.6              0.1

- The expected value E(X) for the given random variable X is:

                E ( X ) = ∑Xi*P(Xi)

                           = 1*0.3 + 2*0.6 + 3*0.1

                           =1.8

- The variance Var(X) for the given random variable X is:

                Var ( X ) = ∑Xi^2*P(Xi) - [ E(X) ] ^2

                               = 1^2*0.3 + 2^2*0.6 + 3^2*0.1 - 1.8^2

                               = 0.36

- The standard deviation for the given random variable X is:

                σ = √Var(X)

                σ = √0.36

                σ = 0.6

5 0
4 years ago
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