Answer:
Actually, it’s not the DNA itself cannot leave the nucleus, but the Chromosome or Chromatin. Because, in the nucleus, DNAs are folded into Chromatin or Chromosome. Chromatin or Chromosome just like a rope, and the DNA just the fiber. It’s the rope cannot escape from the nucleus instead of the fibers.
Explanation:
Even though there are no choices given in this particular question, the principle of osmosis is very easy to understand.
When we talk about osmosis, we are referring to the movement of water from a low concentration to a higher concentration. This is different from diffusion, which talks specifically about the movement of <em>solutes</em> in the solution (from a higher concentration to a lower concentration.)
When an RBC is placed inside a <em>hypertonic </em>solution, the water inside the RBC will go out thereby shrinking the RBC.
Inside an <em>isotonic</em> solution, the RBC will remain the same because the concentrations are equal.
Inside a <em>hypotonic</em> solution, the RBC will lyse or explode because water will move from the solution going inside the RBC.
Gemstone :) Is a rare and attractive mineral that can be worn as jewelry
Answer:
Explanation:
The Genotype of the woman is XCbXN
The man XNY
Since the allele for the color blindness is carried on one of the X -chromosomes of the carrier mother, then the male children will be color blind or carrier deopending on the defective gene they inherited. Since they will receive the defective or normal allele from the mothers,but the female will carriers or normal because they will inherit either defective allele or normal allele from the mother,but normal X allele from the father.
Assuming the colorbind gene was inherited by One of the boys, and the girls take the defective genes
1. XNY vs XCbXN.Then the one of the boys will be colorblind and the one of girls will be carriers. XNXCb, XNXN, XCbY,XNY 50 %
2.If the two boys take the effective genes from the mothers. and none of the girls take the defective alelle
Then the two boys will be colorblind and the girls will be carrries XcbY,XcbY and XNXN XNXN.(normal girls).
The proportions that will be the females since the girls can only take the defective allele from one of the normal and defective allele from the mother. Assuming the girls take the defective allele from the mothers and take normal from the father,they will all be carriers,since the X of the father is normal.
They can not have a color blind girl.Since the father is normal It takes two colorblind X-chromosome to give a girl.
