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Over [174]
3 years ago
10

Which three lengths could be the lengths of the sides of a triangle?

Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0

Answer:

None of the sides can be a triangle.

Step-by-step explanation:

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Explain how you got the answer
Gnoma [55]

Answer:

\huge\boxed{Center = (3,3),Radius = 2\sqrt{15} }

Step-by-step explanation:

<u><em>Given equation is</em></u>

x^2 + y^2 -6x-6y -42 = 0

Adding 42 to both sides

x^2 + y^2 -6x-6y = 42\\

Completing squares

x^2 -6x+y^2 -6x = 42\\(x)^2 - 2(x)(3) +y^2 - 2(y)(3) = 42

Adding (3)² => 9 and (3)² => 9 to both sides

(x-3)^2+(y-3)^2 = 42+9+9\\(x-3)^2 + (y-3)^2 = 60\\(x-3)^2  (y-3)^2 = (2{\sqrt{15})^2}

Comparing it with (x-h)^2+(y-k)^2 = r^2 where Center = (h,k) and Radius = r

We get:

Center = (3,3)

Radius = 2\sqrt{15}

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