A polynomial function of least degree with integral coefficients that has the
given zeros 
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros
Now we multiply it to get the polynomial
polynomial function of least degree with integral coefficients that has the
given zeros
Learn more : brainly.com/question/7619478
When x = -2, y = -5
When x = -1, y = -4
When x = 0, y = -3
When x = 1, y = -2
When x = 2, y = -1
Now plot these points on the graph: (-2,-5), (-1,-4), (0,-3), (1,-2), (2,-1)
Answer:
Arc length of the partial circle = 3π units
Step-by-step explanation:
Given question is incomplete; please find the complete question attached.
Formula for the arc length of a circle = 
Here θ is the angle formed by the sector at the center.
Angle that is formed at the center of the circle is = 360° - 90°
= 270°
So, length of the arc = 
= 3π
Therefore, length of the given partial circle is 3π units.
Answer:
half hour
Step-by-step explanation:
Do 1 fourth times two
