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Verizon [17]
3 years ago
14

Is the line through points p(-8,-4) and Q(5,0) parallel to the line through points R(0,1) and s(-1,-1) ?

Mathematics
1 answer:
vodomira [7]3 years ago
7 0

Answer:

No, they are not parallel

Step-by-step explanation:

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What’s the correct answer for this question?
xxMikexx [17]

Answer:

12.22

Step-by-step explanation:

To find HI, you have to use tangent. tanx=\frac{opposite}{adjacent}

tan(42°)=\frac{11}{HI} , then you multiply HI to both sides of equation and divide tan(42).

To get <em>HI</em>=\frac{11}{tan(42)}

Which makes HI equal 12.2167

5 0
3 years ago
Where is .25, .5, and .75, on a graph?
STALIN [3.7K]
Before the 1 on the x-axis
8 0
3 years ago
After sales tax, a $600 antique clock costs $642. What is the sales tax percentage?
LenKa [72]

well, clearly the tax is the added 42 bucks, so hmmm if we take 600 to be the 100%, how much is 42 off of it in percentage?

\begin{array}{ccll} amount&\%\\ \cline{1-2} 600 & 100\\ 42& x \end{array} \implies \cfrac{600}{42}=\cfrac{100}{x}\implies \cfrac{100}{7}=\cfrac{100}{x} \\\\\\ 100x=700\implies x=\cfrac{700}{100}\implies x=7

5 0
2 years ago
Read 2 more answers
Brielle exercises for 3/4 hour each day for 6 days in a row. Altogether how many hours does she exercise during the 6 days. How
Ksivusya [100]
3/4hr × 6days = 4.5hrs
3 0
4 years ago
This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,
Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Person has the flu.
  • Event B: Person got the flu shot.

The percentages associated with getting the flu are:

  • 20% of 30%(got the shot).
  • 65% of 70%(did not get the shot).

Hence:

P(A) = 0.2(0.3) + 0.65(0.7) = 0.515

The probability of both having the flu and getting the shot is:

P(A \cap B) = 0.2(0.3) = 0.06

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

7 0
2 years ago
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