PLEASE everytime I ask a question I waste my points because people don't want to help!

1 answer:

3 0

Hopefully this is what you mean:

In order to get a bonus this month, Leon must sell at least 120 newspaper subscriptions. He sold 85 subscriptions in the first three weeks of the month. How many subscriptions must Leon sell in the last week of the month?

Solution
Let x = the number of subscriptions Leon sells in the last week of the month. The total number of subscriptions for the month must be greater than 120, so we write :
85 + x ≥ 120.
We solve the inequality by subtracting 85 from both sides: x ≥ 35.

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A manufacturing company employs two devices to inspect output for quality control purposes. The first device is able to accurate

Feliz [49]

Answer:

(a) fxy(x,y) = f(x), f(y)

(b) fx(x) = X = (99.3/100) x 4 = 3.972

(d) fy/2y = (99.7/100) of (2 x 4) = 7.976

(e) E(Y | X = 2) = 2.

(f) V(Y | X = 2) = 2

Step-by-step explanation:

fxy(x,y) = f(x), f(y), as the question presented the assumption that the devices are independent, their measurements must also be independent

Since the first device is able to accurately detect 99.3% of the defective items it receives and the total defective items sent is 4,

(b) fx(x) = X = (99.3/100) x 4 = 3.972

(d) fy/2y = (99.7/100) of (2 x 4) = 7.976

(Since the first device is able to accurately detect 99.7% of the defective items it receives and the total defective items sent is 4)

(e) E(Y | X = 2) = 2. If the second device measure 2 defective items (X = 2), first device will also detect 2 because the measure 99.3% and 99.7% accurately. Their measurements will be approximately equal.

f. V(Y | X = 2). Like the explanation for (e) above, any relations V(Y | X = 2) will also be 2

(g) X and Y are independent because the are measure

measurements on two different devices

4 0

3 years ago

During the past six months, 73.2 percent of US households purchased sugar. Assume that these expenditures are approximately norm

Mrrafil [7]

Answer:

75.94% of the households spent between $5.00 and $9.00 on sugar.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 8.22, \sigma = 1.10$