We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer : 4 cm
Step-by-step explanation:
Hi, the radius of a cone is the radius of its circular base.
Since we know the diameter value (8 centimeters) we have ot apply the next formula:
Diameter = radius x 2
Replacing with the values given
8 = 2r
Solving for r:
8/2=r
4=r
So, the radius of the cone is 4 centimeters.
Feel free to ask for more if needed or if you did not understand something.
Answer:
The value of a = - 1 , And b = 
Step-by-step explanation:
Given as :
Function f(x) = 
And f(f(1)) = 0 And f(2) = - 3
Now For , x = 2 , y = - 3
I.e f(2) = 
or, - 3 =
I.e 2 + a = - 6 - 3b
Or, a + 3b = - 8 ....... 1
Again f(f(1)) = 0
So, 
= 0
Or, 1 + a = 0
∴ a = - 1
So , put htis value of a i n eq 1 , we get value of b
So , - 1 + 3b = - 8
Or, 3b = - 7
∴ b =
Hence The value of a = - 1 , And b = Answer
written answer in the picture
