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Artyom0805 [142]
2 years ago
12

a certain state the license plate has two digits, then two letters, and then two digits. How many different license plates are p

ossible if letters and digits cannot be repeated?
Mathematics
2 answers:
xxTIMURxx [149]2 years ago
7 0

Step-by-step explanation:

Choosing 4 digits out of 10 = 10C4 = 210.

Arranging the 4 digits in 4 places = 4!

Total number of ways to arrange digits

= 210 * 4! = 5040.

Choosing 2 letters out of 26 = 26C2 = 325

Arranging the 2 letters in 2 places = 2!

Total number of ways to arrange letters

= 325 * 2! = 650.

Total number of possible license plates

= 5040 * 650 = 3,276,000.

Evgesh-ka [11]2 years ago
3 0

Answer:

3,276,000

Step-by-step explanation:

10 x 9 x 26 x 25 x 8 x 7 = 3,276,000

the numbers 10, 9, 8, 7 are the spaces available for a non-duplicated digit

the numbers 26 and 25 are for two non-duplicated letters

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Need help with it asap you need to show your work
lawyer [7]

Answer:

the correct answer is 21

Step-by-step explanation:

5+3×3(2)-2

5+18-2

=21

4 0
2 years ago
The height of a flagpole is one-quarter of the height of a bridge.
DedPeter [7]

Answer:

the height of the flagpole is three fourths the height of the school. the difference in there heights is 4.5 m. what is the height of the school?

----------

Equation:

f = (3/4)s

s-f = 4.5

----

Substitute for "f" and solve for "s":

s-(3/4)s = 4.5

 

(1/4)s = 4.5

s = 4*4.5

s = 18 meters (height of the school)

---------------

Since f = (3/4)s, f = (3/4)(18)

= (3/2)(9)= 13.5 meters (height of the flag pole)

===============================-step explanation: HOPE THIS HELPS

6 0
3 years ago
Read 2 more answers
The 3 by 3 grid below shows nine 1 cm × 1 cm squares and uses 24 cm of wire. What length of wire is required for a similar 20 by
Nady [450]

Answer:

840

Step-by-step explanation:

Hi there!

Usually, this kind of problem asks us the perimeter rather than the area. But when talking on this grid on how many cms are necessary to construct one made up of 9 squares 1cm x1 cm. We need to check one thing: Some line segments will be used twice. So this is not a classical perimeter question.

1) So we either manually and carefully count it avoiding not doing it twice the same common line segments.

Or.

2) By just applying an algorithm, Where n is the <em>nxn</em> grid

n(n+1)+n(n+1)=Length \:of \:the \:wire

So, for the 20x20 grid

20(20+1)+20(20+1)=length\\\\20(21)+20(21)=length\\length=840 cm

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3 years ago
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I think the answer should be B linear decay
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The answer is 30. Hope that helps :D
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