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Artyom0805 [142]
2 years ago
12

a certain state the license plate has two digits, then two letters, and then two digits. How many different license plates are p

ossible if letters and digits cannot be repeated?
Mathematics
2 answers:
xxTIMURxx [149]2 years ago
7 0

Step-by-step explanation:

Choosing 4 digits out of 10 = 10C4 = 210.

Arranging the 4 digits in 4 places = 4!

Total number of ways to arrange digits

= 210 * 4! = 5040.

Choosing 2 letters out of 26 = 26C2 = 325

Arranging the 2 letters in 2 places = 2!

Total number of ways to arrange letters

= 325 * 2! = 650.

Total number of possible license plates

= 5040 * 650 = 3,276,000.

Evgesh-ka [11]2 years ago
3 0

Answer:

3,276,000

Step-by-step explanation:

10 x 9 x 26 x 25 x 8 x 7 = 3,276,000

the numbers 10, 9, 8, 7 are the spaces available for a non-duplicated digit

the numbers 26 and 25 are for two non-duplicated letters

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Choose any 2 points from the table:

<span>*10----------------------$25
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Which expression is equivalent to one over five m − 20? (4 points)
exis [7]

Answer:

The equivalent to one over five m − 20 is one over five (m − 100) ⇒ B

Step-by-step explanation:

Let us solve the question

∵ One over five means \frac{1}{5}

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→ By using the distributive property, take one over five as a common factor

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∴ \frac{1}{5} m - 20 = \frac{1}{5} (\frac{\frac{1}{5}m}{\frac{1}{5}} - \frac{20}{\frac{1}{5}})

→ Simplify the bracket

∵  \frac{1}{5} m ÷ \frac{1}{5} = \frac{1}{5} m × 5 = m

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