Answer:
the correct answer is 21
Step-by-step explanation:
5+3×3(2)-2
5+18-2
=21
Answer:
the height of the flagpole is three fourths the height of the school. the difference in there heights is 4.5 m. what is the height of the school?
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Equation:
f = (3/4)s
s-f = 4.5
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Substitute for "f" and solve for "s":
s-(3/4)s = 4.5
(1/4)s = 4.5
s = 4*4.5
s = 18 meters (height of the school)
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Since f = (3/4)s, f = (3/4)(18)
= (3/2)(9)= 13.5 meters (height of the flag pole)
===============================-step explanation: HOPE THIS HELPS
Answer:
840
Step-by-step explanation:
Hi there!
Usually, this kind of problem asks us the perimeter rather than the area. But when talking on this grid on how many cms are necessary to construct one made up of 9 squares 1cm x1 cm. We need to check one thing: Some line segments will be used twice. So this is not a classical perimeter question.
1) So we either manually and carefully count it avoiding not doing it twice the same common line segments.
Or.
2) By just applying an algorithm, Where n is the <em>nxn</em> grid

So, for the 20x20 grid
I think the answer should be B linear decay
The answer is 30. Hope that helps :D