Answer:
Step-by-step explanation:
To prove that
is a multiple of 7.
Proof by induction:
Let n =1. Then we have 8-1 =7 is a multiple of 7
Thus the P(1) is true.
Let us assume that P(n) is true.
= 7l is true for some integer l
To check for P(n+1)
=LHS
=
Thus we find that this is also a multiple of 7.
If true for n, then true for n+1
Hence we find that since true for 1, we have it is true for all natural numbers.
This equation would not be correct.
In the left expression, cscAsecA contains the variable 'e' which is not present in the second expression.
Answer:
i depends on what the equation is.