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Gemiola [76]
3 years ago
5

Pooky eats three cans of cat food each day. How long will 27 cans of food last?

Mathematics
2 answers:
djverab [1.8K]3 years ago
3 0

Answer:

9

Step-by-step explanation:

27/3=9

IgorC [24]3 years ago
3 0

Answer:

9

Step-by-step explanation:

27/3=9

27 cans, divided by 3 cans a day equals 9 days

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Find the value of x.
omeli [17]

Answer:

x=45.5

Step-by-step explanation:

sum of angles of a quadrilateral is 360°

so 3x - 11+x+8+x-8+2x+7+x=360°

or 8x-4=360

or, x=364÷8

hence

x=45.5

8 0
2 years ago
Make d the subject of the formula h = d/3 + 2​
Thepotemich [5.8K]
First what you would have to do is distribute the reciprocal to the (d/3 + 2) and the d/3 is canceled out. You are left with h=6/d. When you put the h over 1 in a fraction, it stays the same. Like in trig, you switch the d and the h and you have d/1=6/h.

d=6/h
4 0
2 years ago
Who is correct and why?
Deffense [45]
There is no information below to give an answer .
6 0
3 years ago
the distance from school to Zoie's house is 3km469m. Jamie's house is 4km301m farther away from Zoie's. How far is it from Jamie
levacccp [35]
Hi there,

To travel from Jamies house to the school, you would have to travel is 7km770m.

I hope my answer has satisfied your request and that you continue to use this website for your schooling.

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Dus4nR
3 0
3 years ago
For the love of God help me !! I'm desperate for it tomorrow
Eduardwww [97]
Try to relax.  Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before.  But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this:  (2)^a negative power = (1/2)^the same power but positive.

So: 
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.

What I just said in that paragraph was:  log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract  log₂(x)  from each side: 

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract  log(base 1/2) (x-2)  from each side:

log₂(x-1) - log₂(x)  =  - log(base 1/2) (x-2)  Notice the negative on the right.

The left side is the same as  log₂[ (x-1)/x  ]

==> The right side is the same as  +log₂(x-2)

Now you have:  log₂[ (x-1)/x  ]  =  +log₂(x-2)

And that ugly [ log to the base of 1/2 ] is gone.

Take the antilog of each side:

(x-1)/x = x-2

Multiply each side by 'x' :  x - 1 = x² - 2x

Subtract (x-1) from each side:

x² - 2x - (x-1) = 0

x² - 3x + 1 = 0

Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .

I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.


There,now.  Doesn't that feel better. 
 






4 0
2 years ago
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