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Mathematics

1 answer:

Nadya [2.5K]3 years ago

5 0

$\dfrac{3.4\cdot10^{-25}}{1.7\cdot10^{-27}}=\dfrac{3.4}{1.7}\cdot10^{-25-(-27)}\\\\=2\cdot10^{-25+27}=2\cdot10^2=2\cdot100=200$
A lead atom has about 200 times more mass.

Used:
$\dfrac{a^n}{a^m}=a^{n-m}$

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PLZZ help 40pts

lyudmila [28]

Answer: At noon the temperature outside of Hector's home was 4 degree warmer than the temperature outside of gale's home.

Step-by-step explanation:

Here, x represents the number of hours after noon while g(x) and f(x) represents the temperature of gale's and hector's home respectively in x hours.

Since, at noon, x = 0

And, by the table g(x=0) = -1

That is, the temperature of gale's home is -1° F at noon.

And, by the given graph, f(x=0) = 3

That is, the the temperature of hector's home is 3° F at noon.

And, f(0)-g(0) = 3-(-1) = 4°F

That is, the difference between the temperature of hector's home at noon and the temperature of gale's home at noon is 4°F.

6 0

3 years ago

Read 2 more answers

Solve for x: 3|x − 3| + 2 = 14

sammy [17]

$\left\{\begin{array}{ccc}a&for& a\geq0\\-a&for&a \ \textless \ 0\end{array}\right \\\\3|x-3|+2=14\ \ \ |subtract\ 2\ from\ both\ sides\\\\3|x-3|=12\ \ \ \ |divide\ both\ sides\ by\ 3\\\\|x-3|=4\iff x-3=4\ or\ x-3=-4\ \ \ |add\ 3\ to\ both\ sides\\\\\boxed{x=7\ or\ x=-1}$