Answer:
The value of BK is 3m and the value of CK is 2.4m.
Step-by-step explanation:
Given information: ABCD trapezoid
, BC=1.2m, AD=1.8m
, AB=1.5m, CD=1.2m
, AB∩CD=K.
Using the given information draw a figure.
Two sides of a trapezoid are parallel.
Since AB∩CD=K, therefore AB and CD are not parallel, because parallel line never intersect.
(Corresponding angles)
(Corresponding angles)
By AA rule of similarity
Corresponding sides of similar triangles are proportional.
The length of BK is 3 m.
The length of CK is 2.4 m.
The answer to the statement is 1/x-1.
Applying the inscribed angle theorem, the measure of arc AB that doesn't go through point C is: 100 degrees.
<h3>What is the Inscribed Angle Theorem?</h3>
Based on the inscribed angle theorem, if ∅ is the inscribed angle measure, the measure of the central angle subtended by the same arc equals 2(∅).
m∠BAC = 40 degrees.
Central angle = 2(40) = 80 degrees [based on the inscribed angle theorem]
Corresponding arc BC = 80 degrees.
Arc AC through point B = 180 degrees [half circle]
Arc AB = 180 - arc BC = 180 - 80 = 100 degrees.
Learn more about the inscribed angle theorem on:
brainly.com/question/3538263
#SPJ1
Answer:
3. 10000
Step-by-step explanation:
Given the following :
Number of gumball cartons = 3
Number of boxes per carton = 100
Number of gumballs per box = 100
The number of gumballs can be expressed in the form : (a. 10) ; where ; a = prime number ; b = whole number
Values of a and b?
Total number of gumballs :
Number of carton × number of boxes per carton × number of gumballs per box
3 × 100 × 100
Hence, writing the expression in the form: a. 10
a. 10 = 3 × 10000
Answer:
80π
Step-by-step explanation:
Circle O with radius IO:
large radius = IO = 12 = R
Circle O with diameter JK
IJ = JK = KL = 2 × IO = 24
IJ = JK = KL = 24/3 = 8
small radius = 8/2 = 4 = r
The shaded area is a semicircle of radius 12 minus a semicircle of radius 4 plus two semicircles of radius 4.
That is the same as
1 semicircle of radius 12 plus 1 semicircle of radius 4
A = πR²/2 + πr²/2
A = π(12² + 4²)/2
A = 160π/2
A = 80π
