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djverab [1.8K]
3 years ago
8

A rocket is launched into the air. The height h(t), in yards, of the rocket is a function of time, t, in seconds, as shown in th

e following table.
t h(t)
0 0
1 20
2 28
3 33
4 28
5 20
6 0
What is the rocket's average rate of change from 3≤t≤6 in yards/second?
Mathematics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

Step-by-step explanation:

Average rate of change is the same thing as the slope.  Because this is parabolic, we cannot find the exact rate of change as we could if this were a linear function.  But we can use the same idea.  When t = 3, h(t) = 33, so the coordinate point is (3, 33).  When t = 6, h(t) = 0, so the coordinate is (6, 0).  Plug those values into the slope formula:

m=\frac{0-33}{6-3} and

m=\frac{-33}{3} which is -11

From 3 to 6 seconds, the rocket is falling 11 yards per second.

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Solution

Part 3

For this case we have 6 different terms

Part 4

We can do the following:

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Part 5

And we can simplify on this way:

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7 0
3 years ago
The area of a square is 49 square meters. How long is each side?
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4 0
3 years ago
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1. Find the slope.

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