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Bess [88]
3 years ago
15

Find a third angle of a right triangle if one of the angles measures 24°.

Mathematics
1 answer:
WITCHER [35]3 years ago
3 0
Well from what we know about triangle is that they all add up to 180 degrees!

A right triangle would have a 90 degree angle and from the given measurements we know that the other on is 24 degrees.

So we simply subtract!! 

180 - 90 = 90 degrees

90 - 24 = 66 degrees

So the measure of the third angle is 66 degrees. :)

Hope this helps. c:
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Need your help now please; the assignment is due tonight and this is the last problem I am having trouble with. The red box is t
Kobotan [32]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

here:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8)  from the graph, we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Therefore;

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

3 0
1 year ago
Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs
Roman55 [17]

Answer:

The area of the triangle is 18 square units.

Step-by-step explanation:

First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:

AB

AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}

AB \approx 7.616

BC

BC = \sqrt{(-1-5)^{2}+(4-6)^{2}}

BC \approx 6.325

AC

AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}

AC \approx 5.831

Now we determine the area of the triangle by Heron's formula:

A = \sqrt{s\cdot (s-AB)\cdot (s-BC)\cdot (s-AC)} (1)

s = \frac{AB+BC + AC}{2} (2)

Where:

A - Area of the triangle.

s - Semiparameter.

If we know that AB \approx 7.616, BC \approx 6.325 and AC \approx 5.831, then the area of the triangle is:

s \approx 9.886

A = 18

The area of the triangle is 18 square units.

7 0
2 years ago
Simplify:- ~~~~~~~
Alchen [17]

\sf \dashrightarrow \:  -  \frac{2}{5}  - ( -  \frac{3}{10} ) - ( -  \frac{4}{7} )

When there is a - in front of an expression in parentheses, change the sign of each term in the expression to +

\sf \dashrightarrow \:  -  \frac{2}{5}    + \frac{3}{10}  +  \frac{4}{7}

Calculate the LCM of denominators

\sf\frac{ - 28 + 21 + 40}{70}

Calculate the difference

\bf \underline{ \underline \frac{33}{70} }

7 0
2 years ago
Read 2 more answers
Giving 25 points for whoever answers it with a complete explanation .. ASAP
MAXImum [283]
No, it is not a function.
Since all the lines have been drawn in the grid line do not have any connection between them even a point in common.
I hope this has been useful for you.
8 0
2 years ago
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What are the steps to solving this problem K + 8\5 = 1k
DaniilM [7]

-- Subtract K from each side of the equation.

8/5 = 0

-- There is no value for K that can make this a true statement. So the original equation has no solution.

8 0
3 years ago
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