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Maslowich
3 years ago
5

Which expressions are equivalent to the given expression?

Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer: 1/ x^2y^5 or the third option from the top

Step-by-step explanation:

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Lilly had 14 pieces of chocolate. She wanted to give her friend 3/7 of the chocolate. How many pieces did she give to her friend
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She gave her friend 6 pieces, just multiply 14 by 3/7! hope it helped
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A rectangle has a length of 11 meters less than 10 times its width. If the area of the rectangle is 9888 square meters, find the
kobusy [5.1K]

Step-by-step explanation:

The Length ,

L

=

284

f

t

.

Explanation:

Given:

Rectangle

Area,

A

=

8804

f

t

2

let W bet he width of the rectangle

L be the length of the rectangle

L

=

10

W

−

26

E

q

u

a

t

i

o

n

1

substitute to

e

q

u

a

t

i

o

n

2

A

=

(

L

)

(

W

)

e

q

u

a

t

i

o

n

2

A

=

(

10

W

−

26

)

(

W

)

8804

=

(

10

W

−

26

)

(

W

)

factor

8804

=

2

(

5

W

−

13

)

(

W

)

divide both sides by 2

4402

=

(

5

W

−

13

)

(

W

)

4402

=

5

W

2

−

13

W

transposing 4402 to the right side of the equation

0

=

5

W

2

−

13

W

−

4402

by quadratic formula

W

=

−

(

−

13

)

+

√

(

−

13

)

2

−

4

(

5

)

(

−

4402

)

2

(

5

)

W

=

[

13

+

√

169

+

88040

]

10

W

=

13

+

(

√

88209

)

10

W

=

13

+

297

10

W

=

310

10

W

=

31

ft

Thus ,

L

=

10

W

−

26

=

10

(

31

)

−

26

L

=

284

f

t

.

answer

W

=

−

(

−

13

)

−

√

−

(

−

13

2

)

−

4

(

5

)

(

−

4402

)

2

(

5

)

this is discarded since this will yield a negative

8 0
3 years ago
Write an equivalent expression for- <br> 3 (4+2)
aliya0001 [1]
Just simplify it :18
7 0
3 years ago
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The mean annual premium for automobile insurance in the United States is $1503 (Insure website, March 6, 2014). Being from Penns
romanna [79]

Answer:

If we compare the p value and the significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean annual premium in Pennsylvania is significantly lower than the national mean annual premium of 1503 at 5% of significance.

Step-by-step explanation:

1) Data given and notation  

\bar X=1440 represent the mean annual premium value for the sample  

s=165 represent the sample standard deviation for the sample  

n=25 sample size  

\mu_o =1503 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean annual premium in Pennsylvania is lower than the national mean annual premium, the system of hypothesis would be:  

Null hypothesis:\mu \geq 1503  

Alternative hypothesis:\mu < 1503  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{1440-1503}{\frac{165}{\sqrt{25}}}=-1.909    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

Since is a one side left tailed test the p value would be:  

p_v =P(t_{(24)}  

Conclusion  

If we compare the p value and the significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean annual premium in Pennsylvania is significantly lower than the national mean annual premium of 1503 at 5% of significance.  

7 0
3 years ago
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