15/60 simplified is 1/4
1/4 is not equal to 3/4
Answer:
Step-by-step explanation:
Since the divisor of 
is in the form of 
we use what is called Synthetic Division. Now, in this formula, −c gives the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
4| 1 1 −17
↓ 4 20
_________
1 5 3 →
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x² + x - 17]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x, the 5 follows right behind it, and bringing up the rear, 
giving you the quotient of 
However, in this case, since you have a remainder of 3, this gets set over the divisor.
I am joyous to assist you anytime.
Depends on the prism!
Here are the basic ones:
SA of rectangular prism = 2lw + 2wh + 2lh OR 2(lw+wh+lh)
SA of triangular prism = 2*area of base + perimeter of base*height
Answer:
130.826 kilojoules
Step-by-step explanation:
The Work required to pump water = pgV
Where, p = density of water = 1000 kg/m³
g = acceleration due to gravity = 9.81ms-¹
V = volume of water
Since, radius r = 5 ft and height h = 9ft
Volume of water in the cylindrical tank = (2/3)πr²h
V = (2/3)π *5²*9 = 471.24 ft³ = 471.24 * 0.0283m³ = 13.336m³
Work required = 1000*9.81*13.336
W = 130.826 KJ
Therefore, the work required to pump water 2/3 of the volume of the cylindrical tank = 130.826 kilojoules.
