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Natalka [10]
3 years ago
14

The first term of an arithmetic sequence is 5. if the25th term is 101 find the common difference?

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
8 0
An arithmetic sequence is one where each term is a constant difference, called the common difference, from the preceding term.  The arithmetic sequence can always be expressed as:

a(n)=a+d(n-1), a=first term, d=common difference, n=term number.

We are given two terms and term numbers, so we can solve for the common difference...

101=5+d(25-1)

101=5+25d-d

101=5+24d

96=24d

d=4

So the common difference is 4.


horrorfan [7]3 years ago
5 0
First term  a1 = 5

25th term = a1 + 24d = 101   (where d = common difference)

5 + 24d = 101
24d = 96 
d = 96/24  = 4

common difference = 4
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Use compound interest formula

\\ \rm\Rrightarrow P(1+r/100)^t=500

\\ \rm\Rrightarrow 100(1+0.25)^t=500

\\ \rm\Rrightarrow (1.25)^t=5

\\ \rm\Rrightarrow log(1.25)^t=log5

\\ \rm\Rrightarrow tlog1.25=log5

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Option A

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2 years ago
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Step-by-step explanation:

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3 0
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