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liraira [26]
4 years ago
15

Betty has 32 hair ribbons she gave 0.25 of the ribbons to Sheri she gave 0.5 of the remaining ribbons to Marcy she kept the rema

ining ribbons how many ribbons did each girlhave
Mathematics
2 answers:
GarryVolchara [31]4 years ago
8 0
Do you mean 25 and 50 percent of the ribbons?

jeyben [28]4 years ago
8 0
I think the answer is 31.25
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Suppose y varies directly as x. if y = 3 when x = 15, find when y = 5.​
julia-pushkina [17]

Answer:

              X = -9

Step-by-step explanation:

y = k X for some fixed number constant k.

 

-5 = k (15)

 

k = -5/15 = -1/3

 

So y = (-1/3)X

 

When y = 3 ---> 3 = (-1/3)X

                        X = -9

4 0
3 years ago
What is this pls help
lesya692 [45]

The answer is B. 17/4


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3 years ago
Consider having a personal loan that spans 50 years. The loan was only taken out for $1000, but the interest rate was a higher f
Gelneren [198K]

Answer:

2995

Step-by-step explanation:

Convert the problem to an equation using the percentage formula: P% * X = Y.

P is 10%, X is 150, so the equation is 10% * 150 = Y.

Convert 10% to a decimal by removing the percent sign and dividing by 100: 10/100 = 0.10.

1000* 5.99% * 50

7 0
3 years ago
Read 2 more answers
Hey I need a step by step of this!!! Or can you just explain to me how to figure it out step by step!! either is fine
Umnica [9.8K]

Answer:

I believe the answer may be x= 24.5 I'm not certain though

Step-by-step explanation:

The angles inside the triangle must all add up to 180 so we can subtract 80 from 180 to get 98. Now I'm assuming the two undefined angles are equal because of the two angle bisectors that create the second triangle. If I'm correct in assuming that them we can divided 98 by 2 to get 49 which would be the measurement of both bottom angles. Since there's a line bisecting both of them we would then cut that number in half to get 24.5. I hope this helped, I'm not fully certain of this answer though.

4 0
3 years ago
A simple random sample of 64 8th graders at a large suburban middle school indicated that 88% of them are involved with some typ
ZanzabumX [31]
The margin of error of a 98% confidence interval is given by


ME=2.33\left(\sqrt{ \frac{p(1-p)}{n} }\right) \\  \\ =2.33\left(\sqrt{\frac{0.88(1-0.88)}{64}}\right) \\  \\ =2.33\left(\frac{0.1056}{64}\right)=2.33(0.0406) \\  \\ =0.0946
5 0
4 years ago
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