Answer:
V=15.44
Step-by-step explanation:
We have a formula
V=\int^{π/3}_{-π/3} A(x) dx ,
where A(x) calculate as cross sectional.
We have:
Inner radius: 5 + sec(x) - 5= sec(x)
Outer radius: 7 - 5=2, we get
A(x)=π 2²- π· sec²(x)
A(x)=π(4-sec²(x))
Therefore, we calculate the volume V, and we get
V=\int^{π/3}_{-π/3} A(x) dx
V=\int^{π/3}_{-π/3} π(4-sec²(x)) dx
V=[ π(4x-tan(x)]^{π/3}_{-π/3}
V=π·(8π/3-2√3)
V=15.44
We use a site geogebra.org to plot the graph.
Answer:
x=bc-35 over 90
Step-by-step explanation:
Answer:14
Step-by-step explanation:
Answer:
B.) as x --> -∞, f(x) --> ∞ and x --> ∞, f(x) --> ∞
Step-by-step explanation:
F(x) is another way of representing "y". That being said, the question is asking you the behavior of the graph in terms of the y-axis. On both sides of the function, there is an arrow pointing upwards, towards infinite, positive y-values. Therefore, as "x" approaches -∞ and ∞, f(x) is approaching ∞ (positive infinity).
The volume of the cylindrical candle that has a base area of 12.56 inches is 12.56h inches³.
<h3>Volume of of cylinder</h3>
volume of a cylinder = πr²h
where
Therefore,
volume of a cylinder = πr²h
Area of the base = πr²
Therefore,
Area of the base = 12.56 inches²
volume of the cylindrical candle = 12.56h inches³
learn more on volume here: brainly.com/question/11459769
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