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3 years ago

Which of the following is not a perfect square? A. 36 B. 45 C. 64 D. 81 ...?

1 answer:

5 0

In your question, 45 is not a perfect square.
A perfect square is when you divide or multiply the number by itself.
36 is a perfect square because it's factor is 6 x 6 (6,6).
64 is a perfect square because it's factor is 8 x 8 (8,8).
81 is a perfect square because it's factor is 9 x 9 (9,9).

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You roll a 6-sided die with faces numbered 1 through 6, and toss a coin. What is the probability of rolling a 2 or getting heads

valentina_108 [34]

That sounds like an extremely misleading question to me but it would be A since theres a 1/6 chance of getting a 2 on a die and there isnt a 1/2 in the answers so it is A

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3 years ago

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How do i find the scale factor of

astraxan [27]

If you’re looking for x it would be -4/3

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3 years ago

Variables x and y are in direct proportion, and y = 12.5 when x = 25. If x = 40, then y =

BabaBlast [244]

25/12.5 = 40/y
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3 years ago

A town accumulated 2 inches of snow and the depth is increasing by 6 inches every hour. A nearby town ha accumulated 9 inches of

Svetach [21]

Answer: it will take 2.33 hours for the snow fall in both of the towns be equal.

Step-by-step explanation:

Let x represent the number of hours that it will take for the snow fall in both of the towns be equal.

A town accumulated 2 inches of snow and the depth is increasing by 6 inches every hour. This means that in x hours, the depth of snow in the town would be

6x + 2

A nearby town has accumulated 9 inches of snow and the depth is increasing by 3 inches every hour. This means that in x hours, the depth of snow in the town would be

3x + 9

For the snow fall in both of the towns be equal, the number of hours would be

6x + 2 = 3x + 9

6x - 3x = 9 - 2

3x = 7

x = 7/3 = 2.33 hours

8 0

3 years ago

A major retail clothing store is interested in estimating the difference in mean monthly purchases by customers who use the stor

faust18 [17]

Answer:

Critical value is t = 1.9901

Step-by-step explanation:

We are given the results of the sampling :

In-House Credit Card National Credit Card Sample Size : 32 50

Mean Monthly Purchases : $45.67 $39.87

Standard Deviation : $10.90 $12.47

Also, the managers wished to test whether there is a statistical difference in the mean monthly purchases by customers using the two types of credit cards, using a significance level α of 0.05.

Firstly, we will specify our null and alternate hypothesis;

Let $\mu_1$ = Mean Monthly Purchases of In-House Credit Card

$\mu_2$ = Mean Monthly purchases of National Credit Card

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in the mean monthly purchases by customers using the two types of credit cards}

Alternate Hypothesis, $H_0$ : $\mu_1-\mu_2\neq$ 0 {means that there is statistical difference in the mean monthly purchases by customers using the two types of credit cards}

The test statistics that will be used here is Two-sample t-test statistics;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n___1+n_2-_2$

where, $\bar X_1$ = Sample mean Purchases of In-House Credit Card = $45.67

$\bar X_2$ = Sample mean Purchases of National Credit Card = $39.87

$s_p$ = pooled variance

$n_1$ = In-house credit card sample = 32

$n_2$ = National credit card sample = 50

So, degree of freedom of t-value here is (32 + 50 - 2) = 80

Now, at 0.05 significance level, t table gives critical value of t = 1.9901 at 80 degree of freedom.

Therefore, the critical value assuming the population standard deviations are not known but that the populations are normally distributed with equal variances is t = 1.9901.

3 0

3 years ago