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Aleks [24]
3 years ago
9

Which of the following is not a perfect square? A. 36 B. 45 C. 64 D. 81 ...?

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
5 0
In your question, 45 is not a perfect square.
A perfect square is when you divide or multiply the number by itself.
36 is a perfect square because it's factor is 6 x 6 (6,6).
<span>64 is a perfect square because it's factor is 8 x 8 (8,8).
</span><span>81 is a perfect square because it's factor is 9 x 9 (9,9).</span>
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PLS I NEED HELP WITH MY EXAM
Neporo4naja [7]

Answer:

F. a1 = –5, an = 5an-1

Step-by-step explanation:

a1 = -5                    <---- Answer

r = -25/-5 = 5

an =  r(an - 1)

an =  5(an - 1) <---- Answer

Hope this helps!

5 0
3 years ago
Read 2 more answers
If the angles of a triangle are 10 45 and 23 what is the perimerter of the triangle
djverab [1.8K]

Answer:

No Solutions

Step-by-step explanation:

In a triangle, the sum of the angles has to be 180 degrees. It also is impossible to find the length of sides without at least one side, since the range of lengths is practically infinite. There are no solutions to this problem.

3 0
2 years ago
Solve for X in the question
tatyana61 [14]

Answer:

2x-1=x

2x-x=1

x=1

Step-by-step explanation:

4 0
3 years ago
What are the correct answers?
Delvig [45]
1. y= -x - 15
2. y= -4x + 1/2
3. y= 2x + 1
4. y= 2/3x + 3
5. y= -1/2x - 4
6. y= -3x + 13

Glad I could help
8 0
3 years ago
3
Masteriza [31]

Answer:

<h3>Lucas and Zoe will both next visit their mother on 7th of May at the same time.</h3>

Step-by-step explanation:

<em>First</em><em>,</em><em> </em><em>find </em><em>the </em><em>first</em><em> </em><em>multiple </em><em>that </em><em>can </em><em>be </em><em>divisible </em><em>by </em><em>5</em><em> </em><em>and </em><em>8</em><em>:</em>

<em>4</em><em>0</em><em> </em><em>is </em><em>divisible </em><em>by </em><em>5 </em><em>and </em><em>8</em><em>.</em>

<em>Second</em><em>,</em><em> </em><em>find </em><em>the </em><em>days </em><em>in </em><em>April </em><em>and </em><em>subtract </em><em>7</em><em> </em><em>from </em><em>the </em><em>days:</em>

<em>April</em><em>=</em><em>3</em><em>0</em><em> </em><em>days</em><em>.</em>

<em>3</em><em>0</em><em>-</em><em>7</em><em>=</em><em> </em><em>2</em><em>3</em><em> </em><em>days</em><em>.</em>

<em>Finally,</em><em> </em><em>subtract </em><em>2</em><em>3</em><em> </em><em>from </em><em>4</em><em>0</em><em> </em><em>and </em><em>find </em><em>it </em><em>in </em><em>the </em><em>next </em><em>month</em><em>,</em><em> </em><em>which </em><em>is </em><em>May</em><em>:</em>

<em>4</em><em>0</em><em>-</em><em>2</em><em>3</em><em>=</em><em>1</em><em>7</em>

<em>Therefore</em><em>,</em><em> </em><em>they </em><em>will </em><em>both </em><em>next </em><em>visit </em><em>their </em><em>mother </em><em>on </em><em>the </em><em>7</em><em>t</em><em>h</em><em> </em><em>of </em><em>May.</em>

3 0
2 years ago
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