Regular triangular pyramid has 6 cm long base edge and slant height k=9 cm. Find the lateral area of the pyramid.
2 answers:
Answer:
81 cm²
Step-by-step explanation:
Since, the lateral face of a triangular pyramid is a triangle,
Given,
The base edge or the base of one lateral face of pyramid, a = 6 cm,
And, the slant height or the height of the face, k = 9 cm,
Thus, the area of one lateral face of the pyramid,
We know that, a Regular triangular pyramid has 3 lateral faces,
Hence, the total lateral area of the pyramid,
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Answer:
The point representing the y-intercept is: (0, -3)
The black dot represents the y-intercept on the attached graph. It is very clear at y = 0, x = -3.
The point representing the x-intercept is: (10.5, 0)
The red dot represents the x-intercept on the attached graph. It is very clear at x = 0, y = 10.5
Step-by-step explanation:
Given the linear equation
-2x+7y=-21
Determining the y-intercept
We know that the value of y-intercept can be determined by setting x = 0, and determining the corresponding value of y.
substituting x = 0 in the equation
-2x+7y=-21
-2(0) + 7y = -21
0+7y = -21
7y = -21
divide both sides by 7
7y/7 = -21/7
y = -3
Therefore, the point representing the y-intercept is: (0, -3)
The black dot represents the y-intercept on the attached graph. It is very clear at y = 0, x = -3.
Determining the x-intercept
We know that the value of x-intercept can be determined by setting y = 0, and determining the corresponding value of x.
substituting y = 0 in the equation
-2x+7y=-21
-2x+7(0) = -21
-2x + 0 = -21
-2x = -21
divide both sides by -2
-2x / -2 = -21 / -2
x = 21/2
x = 10.5
Therefore, the point representing the x-intercept is: (10.5, 0)
The graph of the linear equation containing the y-intercept (0, -3) and x-intercept (10.5, 0) is shown and attached below.
The red dot represents the x-intercept on the attached graph. It is very clear at x = 0, y = 10.5
Please check the attached graph.
