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adelina 88 [10]
3 years ago
10

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

rcuits is tested, revealing 12 defectives.(a) Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool. Round the answers to 4 decimal places.< p\l>(b) Calculate a 95% upper confidence bound on the fraction of defective circuits. Round the answer to 4 decimal places
Mathematics
1 answer:
mafiozo [28]3 years ago
7 0

Answer:

(a) 0.0178 <= p <= 0.0622

(b) p <= 0.0586

Step-by-step explanation:

We have that the sample proportion is:

p = 12/300 = 0.04

(to)

For 95% confidence interval alpha = 0.05, so critical value of z will be 1.96

Therefore, we have that the interval would be:

p + - z * (p * (1-p) / n) ^ (1/2)

replacing we have:

0.04 + - 1.96 * (0.04 * (1-0.04) / 300) ^ (1/2)

0.04 + - 0.022

Therefore the interval would be:

0.04 - 0.022 <= p <= 0.04 + 0.022

0.0178 <= p <= 0.0622

(b)

For upper bounf z-critical value for 95% confidence interval is 1.645, so upper bound is:

p + z * (p * (1-p) / n) ^ (1/2)

replacing:

0.04 + 1.645 * (0.04 * (1-0.04) / 300) ^ (1/2)

0.04 + 0.0186 = 0.0586

p <= 0.0586

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yan [13]

Answer:

80

Step-by-step explanation:

<u><em>A = Area of First Rectangle </em></u>

<u><em>B = Area of Second Rectangle </em></u>

<u><em>w = Width</em></u>

<u></u>

12(w)=320+B (1st Equation)

8(w) = B (2nd Equation)

w=B/8 <em><u>(Plug this value of w into the first equation)</u></em>

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<em>To Test This</em>

12x80 = 960

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<h3>960 - 640 = 320 <u><em>Therefore the answer is correct the width is 80</em></u></h3>

<h3 />
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