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Ivahew [28]
3 years ago
15

Jose has scored 607 points on his math tests so far this semester. To get an A for the semester, he must score at least 619 poin

ts.
Part 1 out of 2
Enter an inequality to find the minimum number of points he must score on the remaining tests in order to get an A. Let n represent the number of points Jose needs to score on the remaining tests.


The inequality is + n .
Mathematics
1 answer:
STALIN [3.7K]3 years ago
7 0

Hi there!

607+n=619

619-607=n

n=12

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Sarah sold 66 posters

<em><u>Solution:</u></em>

Let "a" be the number of shirts sold

Let "b" be the number of posters sold

<em><u>Sarah sold a total of 178 t shirts and posters at a festival</u></em>

Therefore,

number of shirts sold + number of posters sold = 178

a + b = 178 ----------- eqn 1

<em><u>She sold 46 more tshirts than poster</u></em>

Number of shirts sold = 46 + number of posters sold

a = 46 + b --------- eqn 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

46 + b + b = 178

2b = 178 - 46

2b = 132

b = 66

Thus she sold 66 posters

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3 years ago
Consider the parametric equations
MArishka [77]

Answer:(a)x^2+2y^2=2

(b)In the attached diagram

Step-by-step explanation:Step 1: Multiply both equations by t

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Step 1:  Multiply both equations by t

xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)

Step 2:We square both equations

(xt)^2=t^2(cost -sint)^2\\(ty)^2(\sqrt{2})^2 =t^2(cost +sint)^2

Step 3: Adding the two equations

(xt)^2+(ty)^2(\sqrt{2})^2=t^2(cost -sint)^2+t^2(cost +sint)^2\\t^2(x^2+2y^2)=t^2((cost -sint)^2+(cost +sint)^2)\\x^2+2y^2=(cost -sint)^2+(cost +sint)^2\\(cost -sint)^2+(cost +sint)^2=2\\x^2+2y^2=2 hopes this helps

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