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babunello [35]
3 years ago
11

What coordinates are 7 units away from (2,−7)

Mathematics
2 answers:
AlekseyPX3 years ago
7 0
One coordinate that is 7 units away from (2,-7) is (2,0). (2,0) is 7 units to the right of (2,-7)

Another coordinate is (9,-7). This one also works.
miskamm [114]3 years ago
4 0

Answer:

(-5,0) & (9-14)

Step-by-step explanation:

and or subtract seven from both and... BOOM you got your answer

You might be interested in
Jack puts the letters of the word BUILDING on pieces of paper and puts the pieces in a bag. He draws two letters without looking
Zepler [3.9K]

there are 8 letters

2/8 to get i on the first draw

1/7 to get i on the second draw (no replacement)

2/8 * 1/7 = 2/56

1/28


The probability is 1/28

5 0
3 years ago
In a certain Algebra 2 class of 25 students, 13 of them play basketball and 11 of them play baseball. There are 4 students who p
Flauer [41]

Answer:

\frac{4}{5}

Step-by-step explanation:

Given: There are 2 classes of 25 students.

            13 play basketball

            11 play baseball.

            4 play neither of sports.

Lets assume basketball as "a" and baseball as "b".

We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)

As given total number of student is 25

Now, subtituting the values in the formula.

⇒P(a∪b)= \frac{13}{25} +\frac{11}{25} -\frac{4}{25}

taking LCD as 25 to solve.

⇒P(a∪b)= \frac{13\times 1+11\times 1-4\times 1}{25} = \frac{20}{25}

∴ P(a∪b)= \frac{4}{5}

Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is \frac{4}{5}.

6 0
3 years ago
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
At a fundraiser, a school group charges $9 for tickets for a "grab bag." You choose one bill at random from a bag that contains
bazaltina [42]

Answer:

3/9

Step-by-step explanation:

6 0
3 years ago
Dose a polygon usually have more sides or more angles
Helen [10]
 i think more angles than sides




4 0
4 years ago
Read 2 more answers
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