2 years ago

What coordinates are 7 units away from (2,−7)

2 answers:

7 0

One coordinate that is 7 units away from (2,-7) is (2,0). (2,0) is 7 units to the right of (2,-7)

Another coordinate is (9,-7). This one also works.

miskamm [114]2 years ago

4 0

Answer:

(-5,0) & (9-14)

Step-by-step explanation:

and or subtract seven from both and... BOOM you got your answer

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Evaluate the expression when x = 4 and y=-5. -5y+x

Maru [420]

Answer:

$29$

Step-by-step explanation:

Step 1: Set x to 4 and set y to -5

$-5y + x$

$-5(-5) + (4)$

$25 + 4$

$29$

Answer: $29$

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7 people are running in a race. If we only care about first, second and third place, how many possible outcomes are there?

mr_godi [17]

$7\cdot6\cdot5=210$

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3 years ago

Type the expression that results from the following series of steps:

hodyreva [135]

Answer:

$\frac{y}{7} -2$

Step-by-step explanation:

Start with y: y
Start with y, divide by 7: (y/7)
Start with y, divide by 7, then subtract 2: (y/7) - 2

Have a lovely rest of your day/night, and good luck with your assignments! ♡

~ ren ⚘

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2 years ago

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Rotate the figure 90 counterclockwise about the origin. Determine the orientation of the rotated figure and place it in the corr

Alborosie

Answer:

see below

Step-by-step explanation:

The rotated location of D' is (-2, 1). The "arrow" points to the left. The attached figure is the best I could do with your distorted image.

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3 years ago

Triangle PQR has vertices at the following coordinates: P(0, 1), Q(3, 2), and R(5, -4). Determine whether or not triangle PQR is

ruslelena [56]

$PQ = \sqrt{(3-0)^2+(2-1)^2}= \sqrt{9+1}= \sqrt{10} \\ QR= \sqrt{(5-3)^2+(-4-2)^2}= \sqrt{4+36}= \sqrt{40} \\PR= \sqrt{(5-0)^2+(-4-1)^2}= \sqrt{25+25}= \sqrt{50}$

PR is the longest side.
The triangle will be right if
PQ² + QR² = PR²

PQ² + QR² = (√10)² + (√40)² = 10 + 40 = 50
PR² = (√50)² = 50
50=50 so, ΔPQR is a right triangle.

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2 years ago

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