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2 years ago

Are there any rules when solving compound inequalities?

Mathematics

1 answer:

zimovet [89]2 years ago

7 0

Answer:

Yes bro

Step-by-step explanation:

To solve a compound inequality, first separate it into two inequalities. Determine whether the answer should be a union of sets ("or") or an intersection of sets ("and"). Then, solve both inequalities and graph.

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7+4(r+3)=9r-6 show work pls AND HELP ASAP

ivanzaharov [21]

$\: \: \: \: \: \:$

$= \: \: \: \: r = 5$

Step-by-step explanation:

$7 + 4(r + 3) = 9r - 6$

distribute 4 through the parentheses

$7 + 4r + 12 = 9r - 6$

add numbers

$19 + 4r = 9r - 6$

move the variable to the left hand side and change its sign

$19 + 9r = - 6$

move the constant to the right hand side and change its sign

$4r - 9 = - 6 - 19$

collect like terms

 $- 5r = - 6 - 19$ 

calculate the difference

$- 5r = - 25$

divide both sides of the equation by -5

 $= \: \: \: \: r = 5$ 

<h2>hope it helps</h2>

7 0

2 years ago

What is the answer to this question 2x + x + x + 2y x 3y x y

nikklg [1K]

Answer:

2 x (3 y^3 + 2)

Step-by-step explanation:

Simplify the following:

2 x + x + x + 2×3 y y x y

2 y×3 y = 2 y^2×3:

2 x + x + x + 2×3 y^2 x y

2×3 = 6:

2 x + x + x + 6 y^2 x y

6 y^2 x y = 6 y^(2 + 1) x:

2 x + x + x + 6 y^(2 + 1) x

2 + 1 = 3:

2 x + x + x + 6 y^3 x

Grouping like terms, 2 x + x + x + 6 y^3 x = 6 x y^3 + (2 x + x + x):

6 x y^3 + (2 x + x + x)

2 x + x + x = 4 x:

6 x y^3 + 4 x

Factor 2 x out of 6 x y^3 + 4 x:

Answer: 2 x (3 y^3 + 2)

3 0

2 years ago

Find x if the mean of the given data is 7. x 12 3 4 3 8 5 11

Vladimir [108]

Answer:

x=10

Step-by-step explanation:

12+3+4+3+8+5+11+10/8=7

6 0

3 years ago

Tom wanted to compare what proceeds he would receive with a simple interest note versus a simple discount note. Both had the sam

Marrrta [24]

A) Simple interest note proceeds are equal to the face value: $18,235.

b) Simple discount note proceeds are the face value less the inerest due,
.. $18,235(1 -0.10*2) = $14,588.

3 0

3 years ago

The principal amount, $4200, earns 3.6% interest compounded monthly.

svlad2 [7]

Answer:

$A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}$

The total amount accrued, principal plus interest, from compound interest on an original principal of $ 4,200.00 at a rate of 3.6% per year compounded 12 times per year over 10 years is $5667.28.

Step-by-step explanation:

a. Write the function that represents the value of the account at any time, t.

The function that represents the value of the account at any time, t

$A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}$

where

P represents the principal amount

r represents Annual Rate

n represents the number of compounding periods per unit t, at the end of each period

t represents the time Involve

b) What will the value be after 10 years?

Given

The principal amount P = $4200

Annual Rate r = 3.6% = 3.6/100 = 0.036

Compounded monthly = n = 12

Time Period = t

To Determine:

The total amount A = ?

Using the formula

$A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}$

substituting the values

$A\:=\:4200\left(1\:+\:\frac{0.003}{12}\right)^{\left(12\right)\left(10\right)}$

$\:A\:=\:4200\left(1.0025\right)^{120}$

$A=5667.28$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 4,200.00 at a rate of 3.6% per year compounded 12 times per year over 10 years is $5667.28.

6 0

2 years ago