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Tamiku [17]
3 years ago
9

How long is a string reaching from the top of a 13-ft pole to a point on the ground that is 7ft from the base of the pole ?

Mathematics
2 answers:
Shalnov [3]3 years ago
8 0
20 feet should be the correct answer. not sure if there's any choices
Genrish500 [490]3 years ago
7 0
The string would represent the hypotenuse of a right triangle.
7^2 + 13^2 = c^2
49 + 169 = c^2
218 = c^2
sqrt 218 = c
14.8 = c

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GarryVolchara [31]

y = 1/4 x because with the y-intercept being zero you don't have to show the integer 0 in the equation.

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3 years ago
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ABCD ~ JKLM. Write a proportion containing BC and JM
Mashutka [201]

Answer:

\frac{BC}{KL} = \frac{AD}{JM}

Step-by-step explanation:

since the triangles are similar then the ratios of corresponding sides are in proportion , that is

\frac{BC}{KL} = \frac{AD}{JM}

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2 years ago
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Type the correct answer in each box use numerals instead of words consider the quadratic equation
irinina [24]
Where are the boxes we’re looking at??
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3 years ago
Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
3 years ago
Determine the margin of error, m , of a 99% confidence interval for the mean IQ score of all students with the disorder. Assume
madreJ [45]

Answer:

E= 6.45

standard deviation is σ = 15,

The critical value is z(α/2) = 2.58.

Step-by-step explanation:

Margin error is the value that is lie above and below the sample.It gives percentage of numbers.Its is the product of critical value standard deviation and standard error of statistic.

General formula for the margin of error is

Margin of error = critical value  ×   standard error of statistic

                        = z \alpha /2  ×   σ √n

z-value from two tailed is listed below:

From the table of standard normal distribution, probability value of 0.10.

row and column values gives the area to the two tail of z.

The positive z value is 2.58.

standard deviation is σ = 15,

The critical value is z(α/2) = 2.58.

after putting these vales we obtain the margin of error value that is

E= 6.45

7 0
3 years ago
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