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Nata [24]
4 years ago
6

What is the solution to this system of equations? What is the solution to the system of equations? (–6, –2) (–2, 6) (6, 2) (–2,

–6) Mark this and return
Mathematics
1 answer:
Sidana [21]4 years ago
5 0

Answer:

a

Step-by-step explanation:

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If a man runs for an hour and a half at 8 miles an hour due south; and then he continues south on a bus traveling at 55 miles an
Usimov [2.4K]

He ran 8 miles per hour.

Multiply his speed by the time he ran to find total distance:

8 mph x 1.5 hours = 12 miles

He ran for 12 miles.

Now Find the distance the bus went:

For time, divide the minutes the bus drove by 60 minutes per hour.

55 miles per hour x 24/60 = 22 miles

The bus went 22 miles.

Total distance = 12 + 22 = 34 miles.

4 0
3 years ago
What is the area when radius=2.6in
fomenos

Answer:

Hope this helps!

Step-by-step explanation:

Area = π · r2 = 3.14 · 2.62 = 21.24 square inches.

7 0
3 years ago
Solve the folloeing equation for a number x. <br><br>5x-x-6=6(2x+7)<br>plllllzzz help
Ray Of Light [21]

Answer:

x=-6

Step-by-step explanation:

5x-x-6=6(2x+7)

4x-6=<em>6(2x+7)</em>

4x-6=<em>12x+</em><em>42</em>

-8x=48 |:(-8)

x=-6

3 0
3 years ago
I need help quickly!!!!
Mademuasel [1]
A) Yes, it starts with the same coordinates. because it start as (0,0)
B) No, it because it (6,3)
C) No, because the line segment goes higher and higher.
D) No, because the domain and range dont repeat.
E) I dont exactly know sorry :/
8 0
3 years ago
Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
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