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DochEvi [55]
3 years ago
11

2 EASY QUESTIONS 6TH GRADE WILL GIVE BRAINLY

Mathematics
2 answers:
Debora [2.8K]3 years ago
5 0

Answer:

15 and 6

Step-by-step explanation:

myrzilka [38]3 years ago
5 0
28 is 15 and 29 is 6
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Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
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Answer: sry just trying to get points

Step-by-step explanation:

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3 years ago
A ramp is placed from a ditch to a main road 2ft. above the ditch. If the length of the ramp is 12ft, how far away is the bottom
Nadusha1986 [10]
See attached picture for solution:

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3 years ago
PLEASE HELP WITH MATH.BEST ANSWER GETS BRAINLIEST. You have to find the volume of the figure below.
castortr0y [4]
Volume = width × height × length. First let's concentrate on the rectangular prism. This has 4 for its height and 5 for its width so you do 4 × 5 (=20) × 10 (because the length of the rectangular prism is the same as the triangular prism, so we will use the length of the triangular one) = 200m³ for the rectangular one. To work out the triangular one, it's the same, but whatever answer you get you divide it by 2 because a triangle is just a rectangle cut in half diagonally. Therefore, 3 × 5 (=15) × 10 = 150. Then divided by 2 = 75m³. Total volume = volume of rectangular prism + triangular prism Therefore total volume = 200 + 75 = 275m³.
6 0
2 years ago
SOS WHAT IS THE SQUARE ROOT OF 144/256?
tangare [24]
The square root is  \sqrt{\frac{144}{256}} = \frac{3}{4} Just square the top and bottom of the fraction. \sqrt{144} = 12 and \sqrt{256} = 16 so we have 12/16 and then we reduce to 3/4
4 0
2 years ago
Read 2 more answers
For the region bounded by y=2x​, the​ x-axis, and x=1​, determine which of the following is​ greater: the volume of the solid ge
telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

\int\limits^1_0 {(pi)y^{2} } \, dx

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0
2 years ago
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