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DedPeter [7]
3 years ago
10

Kevin must choose a number between 61 and 107 that is a multiple of 5, 8, and 10. Write all the numbers that he could choose. If

Mathematics
1 answer:
MrMuchimi3 years ago
3 0

Answer:

80 is a number of 5,8, and 10

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Jim orders prints from a website. The site charges him $6.95 a month and $0.04 for each print he orders.
Alexxandr [17]
P=$17.79-$6.95
P=$10.84
P=$10.84 divide by 0.04
P= 271
Jim ordered 271 prints last month
8 0
3 years ago
Read 2 more answers
In which diagram do angles 1 and 2 form a linear pair?
rodikova [14]

The diagram where angles 1 and 2 form a linear pair is D. A horizontal line has 1 line extending from it. Angles 1 and 2 are formed.

<h3>What is a linear pair?</h3>

It should be noted that a linear pair simply means angles that are formed when two lines intersect each other at a single point.

In this case, when a horizontal line has 1 line extending from it. Angles 1 and 2 are formed. This depicts a linear pair

In conclusion, the correct option is D.

Learn more about linear pair on:

brainly.com/question/13218054

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4 0
2 years ago
Help me!!!!!!!!!!!!!
irakobra [83]
Seven twenty-two am 
7:22am
8 0
3 years ago
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A box contain 12 balls in which 4 are white 3 are blue and 5 are red.3 balls are drawn at random from the box.find the chance th
Anastasy [175]

Answer:

3/11

Step-by-step explanation:

From the above question, we have the following information

Total number of balls = 12

Number of white balls = 4

Number of blue balls = 3

Number of red balls = 5

We solve this question using combination formula

C(n, r) = nCr = n!/r!(n - r)!

We are told that 3 balls are drawn out at random.

The chance/probability of drawing out 3 balls = 12C3 = 12!/3! × (12 - 3)! = 12!/3! × 9!

= 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/(3 × 2 × 1) × (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= 220 ways

The chance of selecting 3 balls at random = 220

To find the chance that all the three balls are selected,

= [Chance of selecting (white ball) × Chance of selecting(blue ball) × Chance of selecting(red balls)]/ The chance/probability of drawing out 3 balls

Chance of selecting (white ball)= 4C1

Chance of selecting(blue ball) = 3C1 Chance of selecting(red balls) = 5C1

Hence,

= [4C1 × 3C1 × 5C1]/ 220

= 60/220

= 6/22

= 3/11

The chance that all three are selected is = 3/11

4 0
3 years ago
What is the expontential form of √13
kaheart [24]
The answer is (13)^1/2
6 0
3 years ago
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