Car X and car Y traveled the same 80-mile route. If car X took 2 hours and car Y traveled at an average speed that was 50 percen
t faster than the average speed of car X, how many hours did it take car Y to travel the route?
1 answer:
Answer:
Step-by-step explanation:
Both cars, X and Y travelled 80 miles each.
Speed = distance/time
If car X took 2 hours to travel 80 miles, it means that the speed at which car X travelled is
80/2 = 40 mph
If car Y traveled at an average speed that was 50 percent faster than the average speed of car X, it means that the speed at which car X travelled is
40 + 0.5 × 40 = 60 mph
Time = distance/speed
Therefore, time taken by car Y to travel 80 miles is
80/60 = 1.33 hours
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