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Thepotemich [5.8K]
3 years ago
8

Car X and car Y traveled the same 80-mile route. If car X took 2 hours and car Y traveled at an average speed that was 50 percen

t faster than the average speed of car X, how many hours did it take car Y to travel the route?
Mathematics
1 answer:
KiRa [710]3 years ago
7 0

Answer:

Step-by-step explanation:

Both cars, X and Y travelled 80 miles each.

Speed = distance/time

If car X took 2 hours to travel 80 miles, it means that the speed at which car X travelled is

80/2 = 40 mph

If car Y traveled at an average speed that was 50 percent faster than the average speed of car X, it means that the speed at which car X travelled is

40 + 0.5 × 40 = 60 mph

Time = distance/speed

Therefore, time taken by car Y to travel 80 miles is

80/60 = 1.33 hours

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Answer:

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Step-by-step explanation:

A rhombus is divided into four congruent triangles. The two given angles are complementary, meaning they add up to 90 degrees. Set up an equation:

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Item 9 a flight averages 460 miles per hour. the return flight averages 500 miles per hour due to a tailwind. the total flying t
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Let us say that the variables for flight is designated by 1, while the return flight by 2, since the distance travelled are equal, therefore:

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or

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t1 = 2.5

 

Answer:

The flight took 2.5 hours while the return flight took 2.3 hours.

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