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Thepotemich [5.8K]
3 years ago
8

Car X and car Y traveled the same 80-mile route. If car X took 2 hours and car Y traveled at an average speed that was 50 percen

t faster than the average speed of car X, how many hours did it take car Y to travel the route?
Mathematics
1 answer:
KiRa [710]3 years ago
7 0

Answer:

Step-by-step explanation:

Both cars, X and Y travelled 80 miles each.

Speed = distance/time

If car X took 2 hours to travel 80 miles, it means that the speed at which car X travelled is

80/2 = 40 mph

If car Y traveled at an average speed that was 50 percent faster than the average speed of car X, it means that the speed at which car X travelled is

40 + 0.5 × 40 = 60 mph

Time = distance/speed

Therefore, time taken by car Y to travel 80 miles is

80/60 = 1.33 hours

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2 years ago
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The hotel is $250 plus $25 per person so the equation would be

y= 25x + 250

(Y is the total cost and x is the number of people)

the restaurant is $100 plus $40 per person so the equation would be

y = 40x + 100

What we want to know is which x value would make the y values equal to each other. So you can just replace the "y" in one equation with the other equation:

25x + 250 = 40x + 100

and then solve...

1. subtract 100 from both sides

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2. subtract 25x from both sides

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3. divide both sides by 15

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you can check by plugging 10 into the original equations

25(10) + 250

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and

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8 0
3 years ago
the test scores for 10 students were 61,67,81,83,87,88,89,90,98, and 100. which frequency table represents this data set?
lana66690 [7]

Answer:

below only shows up once

Step-by-step explanation:

mark: tally:  frequency:

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67   I               I

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83         I            I

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