Answer:
1. x - 12
2. x - ![\frac{8}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D)
3. x + 10
Step-by-step explanation:
1. Divide by -1/2.
-1/2x ÷ -1/2 = x
6 ÷ -1/2 = -12
Add together.
x - 12
2. Divide by 3.
3x ÷ 3 = x
-8 ÷ 3 = -![\frac{8}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D)
Add together.
x - ![\frac{8}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D)
3. Divide by -1.
-x ÷ -1 = x
-10 ÷ -1 = 10
Add together.
x + 10
Answer:
Wrong. If the line segment AB= 10, then the measure of AC= 10 as well. It's a right triangle. All the sides are the same.
Step-by-step explanation:
Answer: I belive it is
94
Step-by-step explanation:
I was going on the phone and I saw the message I sent
Answer:
.
Step-by-step explanation:
We have been given an indefinite integral
. We are asked to find the value of the integral using integration by parts.
Let
,
.
Now, we will find du and v as shown below:
![\frac{du}{dx}=\frac{d}{dx}(\text{ln}(x))](https://tex.z-dn.net/?f=%5Cfrac%7Bdu%7D%7Bdx%7D%3D%5Cfrac%7Bd%7D%7Bdx%7D%28%5Ctext%7Bln%7D%28x%29%29)
![\frac{du}{dx}=\frac{1}{x}](https://tex.z-dn.net/?f=%5Cfrac%7Bdu%7D%7Bdx%7D%3D%5Cfrac%7B1%7D%7Bx%7D)
![du=\frac{1}{x}dx](https://tex.z-dn.net/?f=du%3D%5Cfrac%7B1%7D%7Bx%7Ddx)
![v=\frac{x^{3+1}}{3+1}=\frac{x^{4}}{4}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bx%5E%7B3%2B1%7D%7D%7B3%2B1%7D%3D%5Cfrac%7Bx%5E%7B4%7D%7D%7B4%7D)
Upon substituting our values in integration by parts formula, we will get:
![\int \:x^3\:\text{ln}\:(x)\:dx=\text{ln}(x)*\frac{x^4}{4}-\int\: \frac{x^4}{4}*\frac{1}{x}dx](https://tex.z-dn.net/?f=%5Cint%20%5C%3Ax%5E3%5C%3A%5Ctext%7Bln%7D%5C%3A%28x%29%5C%3Adx%3D%5Ctext%7Bln%7D%28x%29%2A%5Cfrac%7Bx%5E4%7D%7B4%7D-%5Cint%5C%3A%20%5Cfrac%7Bx%5E4%7D%7B4%7D%2A%5Cfrac%7B1%7D%7Bx%7Ddx)
![\int \:x^3\:\text{ln}\:(x)\:dx=\frac{\text{ln}(x)x^4}{4}-\int\: \frac{x^3}{4}dx](https://tex.z-dn.net/?f=%5Cint%20%5C%3Ax%5E3%5C%3A%5Ctext%7Bln%7D%5C%3A%28x%29%5C%3Adx%3D%5Cfrac%7B%5Ctext%7Bln%7D%28x%29x%5E4%7D%7B4%7D-%5Cint%5C%3A%20%5Cfrac%7Bx%5E3%7D%7B4%7Ddx)
![\int \:x^3\:\text{ln}\:(x)\:dx=\frac{\text{ln}(x)x^4}{4}-\frac{1}{4}\int\: x^3dx](https://tex.z-dn.net/?f=%5Cint%20%5C%3Ax%5E3%5C%3A%5Ctext%7Bln%7D%5C%3A%28x%29%5C%3Adx%3D%5Cfrac%7B%5Ctext%7Bln%7D%28x%29x%5E4%7D%7B4%7D-%5Cfrac%7B1%7D%7B4%7D%5Cint%5C%3A%20x%5E3dx)
![\int \:x^3\:\text{ln}\:(x)\:dx=\frac{\text{ln}(x)x^4}{4}-\frac{1}{4}*\frac{x^{3+1}}{3+1}+C](https://tex.z-dn.net/?f=%5Cint%20%5C%3Ax%5E3%5C%3A%5Ctext%7Bln%7D%5C%3A%28x%29%5C%3Adx%3D%5Cfrac%7B%5Ctext%7Bln%7D%28x%29x%5E4%7D%7B4%7D-%5Cfrac%7B1%7D%7B4%7D%2A%5Cfrac%7Bx%5E%7B3%2B1%7D%7D%7B3%2B1%7D%2BC)
![\int \:x^3\:\text{ln}\:(x)\:dx=\frac{\text{ln}(x)x^4}{4}-\frac{1}{4}*\frac{x^4}{4}+C](https://tex.z-dn.net/?f=%5Cint%20%5C%3Ax%5E3%5C%3A%5Ctext%7Bln%7D%5C%3A%28x%29%5C%3Adx%3D%5Cfrac%7B%5Ctext%7Bln%7D%28x%29x%5E4%7D%7B4%7D-%5Cfrac%7B1%7D%7B4%7D%2A%5Cfrac%7Bx%5E4%7D%7B4%7D%2BC)
![\int \:x^3\:\text{ln}\:(x)\:dx=\frac{\text{ln}(x)x^4}{4}-\frac{x^4}{16}+C](https://tex.z-dn.net/?f=%5Cint%20%5C%3Ax%5E3%5C%3A%5Ctext%7Bln%7D%5C%3A%28x%29%5C%3Adx%3D%5Cfrac%7B%5Ctext%7Bln%7D%28x%29x%5E4%7D%7B4%7D-%5Cfrac%7Bx%5E4%7D%7B16%7D%2BC)
Therefore, our required integral would be
.