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pickupchik [31]
2 years ago
11

Write negations for each of the following statements. (Assume that all variables represent fixed quantities or entities, as appr

opriate.)
a. If P is a square, then P is a rectangle.
b. If today is New Year’s Eve, then tomorrow is January.
c. If the decimal expansion of r is terminating, then r is rational.
d. If n is prime, then n is odd or n is 2.
e. If x is nonnegative, then x is positive or x is 0.
f. If Tom is Ann’s father, then Jim is her uncle and Sue is her aunt.
g. If n is divisible by 6, then n is divisible by 2 and n is divisible by 3.
Mathematics
1 answer:
amm18122 years ago
4 0

Answer:

a. P is a square and P is not a rectangle

b. Today is New Year’s Eve and tomorrow is not January.

c. The decimal expansion of r is terminating and r is not rational.

d. n is prime and either n is not odd or n is not 2.

e. x is nonnegative and either x is not positive or x is not 0.

f. Tom is Ann’s father and either Jim is not her uncle or Sue is not her aunt.

g. n is divisible by 6 and either n is not divisible by 2 or n is not divisible by 3.

Step-by-step explanation:

The general formula for negations that will be applied is:

Statement: If x is y, then x is z

Negation: x is y and x is not z

Statement: If x is y, then x is z and w

Negation: x is y and either x is not z or x is not w

Applying those principles:

a. P is a square and P is not a rectangle

b. Today is New Year’s Eve and tomorrow is not January.

c. The decimal expansion of r is terminating and r is not rational.

d. n is prime and either n is not odd or n is not 2.

e. x is nonnegative and either x is not positive or x is not 0.

f. Tom is Ann’s father and either Jim is not her uncle or Sue is not her aunt.

g. n is divisible by 6 and either n is not divisible by 2 or n is not divisible by 3.

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To find a fraction between two fractions, all we need to do is make the sum of the numerators be the new numerator, and the sum of the denominators be the new denominator. then write down the number of rational number you want. if you need more then multiply the denominator and numerator by 10,100.

Step-by-step explanation:

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In one year, a bird farm sold 375 total chickens. of these, there were 37 more Cornish hens than turkeys. How many Cornish hens
GarryVolchara [31]

Answer:

206 Cornish hens

169 turkeys

Step-by-step explanation:

Let c represent the number of Cornish hens sold. Then c-37 is the number of turkeys sold. The total sales would be ...

... c + (c-37) = 375

... 2c = 412 . . . . collect terms, add 37

... c = 206 . . . . Cornish hens sold

... (c-37) = 169 . . . turkeys sold

_____

<em>Comment on this type of problem</em>

Note that the solution to this problem is that the larger number (number of cornish hens) is half the sum of the total and the difference: (375+37)/2 = 206. This is the general solution for this type of "sum and difference" problem.

The larger contributor is half the total plus half the difference; the smaller contributor is half the total minus half the difference.

Cornish hens = (1/2)(375 +37) = 206

Turkeys = (1/2)(375 -37) = 169

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Find the slope of a line that passes through points (-1,-5) and (6,9).
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Answer:

{ \rm{slope =  \frac{y _{2} - y _{1} }{x _{2} - x _{1}  } }} \\  \\ { \rm{slope =  \frac{9 - ( - 5)}{6 - ( - 1)} }} \\  \\ { \rm{slope =  \frac{14}{7} }} \\  \\ { \boxed{ \rm{ \:  \: slope = 2 \:  \: }}}

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By arranging this equation in terms of x and y, we have:


x^2-8x+y^2-6y=-24 \\ \\


By using the method of completing the square, we have:

x^2-8x+\mathbf{\left(\frac{8}{2}\right)^2}+y^2-6y+\mathbf{\left(\frac{6}{2}\right)^2}=-24+\mathbf{\left(\frac{8}{2}\right)^2}+\mathbf{\left(\frac{6}{2}\right)^2} \\ \\ x^2-8x+\mathbf{16}+y^2-6y+\mathbf{9}=-24+\mathbf{16}+\mathbf{9} \\ \\ \boxed{(x-4)^2+(x-3)^2=1}


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