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Mariana [72]
3 years ago
15

make a conjecture, is there a value of N for which there could be a triangle with sides of length N, 2N, and 3N?

Mathematics
1 answer:
Assoli18 [71]3 years ago
6 0

Answer: Conjecture: There is no triangle with side lengths N, 2N, and 3N (where N is a positive real number)

Proof:

We prove this by contradiction: Suppose there was an N for which we can construct a triangle with side lengths N, 2N, and 3N. We then apply the triangle inequalities tests. It must hold that:

N + 2N > 3N

3N > 3N

3 > 3

which is False, for any value of N. This means that the original choice of N is not possible. Since the inequality is False for any value of N, there cannot be any triangle with the given side lengths, thus proving our conjecture.

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Maru [420]

Answer:

Step-by-step explanation:

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a. ∠13 ≅ ∠17                          a║c                  Corresponding angles

b. ∠4 ≅ ∠9                            d║e                  Exterior alternate angles

c. m∠20 + m∠21 = 180°        a║b                  Consecutive interior angles

d. ∠8 ≅ ∠19                                                    Vertical angles

e. ∠10 ≅ ∠23                         b║c                  Interior alternate angles

f.  m∠14 + m∠17 = 180°          a║c                  Consecutive interior angles

6 0
3 years ago
A triangular brace has an angle measure of 30 degrees, with a side opposite
AfilCa [17]
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5 0
3 years ago
Twenty-one less than a number is seven. What is the number?<br> 3<br> 14.<br> 28<br> 147
maks197457 [2]

Answer:

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4 0
3 years ago
Read 2 more answers
What z score in a normal distribution has 33% of all score above it? ap stats quiz 2.2a answers?
Sladkaya [172]

What z score in a normal distribution has 33% of all score above it?

Answer: A z score which has 33% of all scores above it, will have 67% of all scores  below it.

To find the required z score, we need to find the z value corresponding to probability 0.67.

Using the standard normal table, we have:

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Therefore, the z score = 0.44 has 33% of all score above it.


8 0
3 years ago
There are 6 yellow hexagons 2 red trapezoids and 9 green triangles how many flowers could you make if they were changed 30 yello
Zinaida [17]

Answer:

<h3>a) 5 flowers</h3><h3>b) Trapezoid</h3>

Step-by-step explanation:

For one flower, the following shapes are used;

6 yellow hexagons, 2 red trapezoids and 9 green triangles

If we are given 30 yellow hexagons 50 red trapezoids and 60 green triangles, to get the number of flowers we can make, we will find the greatest common factor of 30, 50 and 60

30 = 6*5

50 = (2*5)+40

60 = (9*5)+15

We can see that 5 is common to all the factors. This means that we can make 5 flowers if they were changed to 30 yellow hexagons 50 red trapezoids and 60 green triangles.

Since there are 40 trapezoids left and 15 green triangles left, hence the shape that would have n as left over most is trapezoid (40 left over)

7 0
3 years ago
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