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3 years ago

FIND THE EQUATION OF THE LINE SHOWN: QUICK I NEED TO SUMBIT MY HW

Mathematics

2 answers:

Sergeu [11.5K]3 years ago

5 0

Answer:

the equation of the line is y = -1/4x +2

Step-by-step explanation:

The first step is to see where the line intercepts on the y-axis, which is 2. The next step is to see what the slope is so because it goes down 1 right 4, you find out that the slope of the line is -1/4.

Hope this helps!

lakkis [162]3 years ago

4 0

Answer:

y = -1/4x +2

Step-by-step explanation:

First find the slope using two point

(0,2) and (4,1)

m = (y2-y1)/(x2-x1)

= (1-2)/(4-0)

= -1/4

The y intercept is 2

The slope intercept form of a line is

y= mx+b where m is the slope and b is the y intercept

y = -1/4x +2

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A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

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3 years ago

Here are the LETTERS that goes with the file A=3 B=4 C=6 D=2

Jlenok [28]

Answer:

I think 120

Step-by-step explanation:

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3 years ago

A can of vegetables has radius 2.1 in. and height 5.1 in. Find

Katen [24]

Answer:

70.622 in³

Step-by-step explanation:

Volume of cylinder = $\pi r^2h$

= (3.14)(2.1^2)(5.1)

= 70.622 in³

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3 years ago

Adam plans to choose a video game from a section of the store where everything is 75% off. He writes the expression −0.75 to fin

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

Adam plans to choose a video game from a section of the store where everything is 75% off.

The expression written by him for this situation is d - 0.75d.

Here, the part d represents the sale price before discount and the part 0.75d is the discount amount.

The expression written by Rena is 0.25d.

Here, the part 0.25d is the price after discount. Since 75% is the discount, the rate after disount is 25% and 25% of d is 0.25d.

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3 years ago

HELP ME PLEASEEEEEEEEE

Nataliya [291]

Answer:

a)This solution matches with the original equation and its solution

b)This solution matches with the original equation and its solution

c)This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d)This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

Step-by-step explanation:

i) Which scenarios can be solved by 1.5x + 2.25 = 12.75. Select all that apply and note the given solution.

therefore 1.5x = 10.5 therefore x = 7

a) let the number be x

therefore if $\frac{3}{2} x + \frac{9}{4} = \frac{51}{4} \Rightarrow 1.5x + 2.25 = 12.75$ then the number x = 7.

This solution matches with the original equation and its solution

b.) If a taxi driver charges a flat fee of $2.25 and $1.5 per mile, where the

number of mile = x, then the number of miles Juan can ride the taxi for

$12.75 is x = 7.

This solution matches with the original equation and its solution

c)if nine quarters of a number, say x, increased by three halves is fifty one

quarters, the number is x = 5,

$\frac{9}{4} x + \frac{3}{2} = \frac{51}{4} \Rightarrow 9x = 51 - 6 = 45 \therefore x = 5$

This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d.) If a taxi driver charges a flat fee of $1.5 and $2.25 per mile, where the

number of mile = x, then the number of miles Juan can ride the taxi for

$12.75 is x = 5.

$2.25x + 1.5 = 12.75 \Rightarrow 9x = 51 - 6 = 45 \therefore x = 5$

This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

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4 years ago