The answer is 12.96 cents because there is an extra eight cents for every dollar
To find the future value, you would multiply the starting value from year one by 1+ the percent of increase per year raised to the number of years you want.,
The starting value of the house would be the value from year one: 212,566.20
The equation would then be: f(t) = 212,566.20(1.05)t
122.1 is 222% of 55. Hope his helped you out.
Third term = t3 = ar^2 = 444 eq. (1)
Seventh term = t7 = ar^6 = 7104 eq. (2)
By solving (1) and (2) we get,
ar^2 = 444
=> a = 444 / r^2 eq. (3)
And ar^6 = 7104
(444/r^2)r^6 = 7104
444 r^4 = 7104
r^4 = 7104/444
= 16
r2 = 4
r = 2
Substitute r value in (3)
a = 444 / r^2
= 444 / 2^2
= 444 / 4
= 111
Therefore a = 111 and r = 2
Therefore t6 = ar^5
= 111(2)^5
= 111(32)
= 3552.
<span>Therefore the 6th term in the geometric series is 3552.</span>
Answer:
a=28, b=-15
Step-by-step explanation:
![Method\ by\ linear\ combinaisons\\\left\{\begin{array}{ccc|c|c|}2a+5b&=&-19&-1&3\\3a+5b&=&9&1&-2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&28\\5b&=&-75\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&28\\b&=&-15\\\end{array}\right.\\](https://tex.z-dn.net/?f=Method%5C%20by%5C%20linear%5C%20combinaisons%5C%5C%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Cc%7Cc%7C%7D2a%2B5b%26%3D%26-19%26-1%263%5C%5C3a%2B5b%26%3D%269%261%26-2%5C%5C%5Cend%7Barray%7D%5Cright.%5C%5C%5C%5C%5C%5C%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Da%26%3D%2628%5C%5C5b%26%3D%26-75%5C%5C%5Cend%7Barray%7D%5Cright.%5C%5C%5C%5C%5C%5C%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Da%26%3D%2628%5C%5Cb%26%3D%26-15%5C%5C%5Cend%7Barray%7D%5Cright.%5C%5C)