Answer:
33 degree
Step-by-step explanation:
Let m1 be x
m2= x+1
A/Q
--> m1+m2= 67
--> x+x+1= 67
--> 2x+1=67
--> 2x= 67-1
--> 2x=66
--> x= 66/2
--> x= 33
So, m1= 33 degree
PLEASE MARK ME AS BRAINLIEST:)
<h3>
Answer: B. 17</h3>
The mode is the most frequent or most occurring value. The value 17 shows up the most times, at two times, so this is the mode. The value 19 is not even part of the given set of values, so you can immediately cross of choice A.
Side note: it is possible for a set to have more than one mode, and it's also possible to not have a mode at all.
Answer: yes, aas
Step-by-step explanation:
They have the two angles, and then the side after the angles
We start with the expression at the left of the equation.
We can combine the terms as:
![\begin{gathered} \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}} \\ \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D-%5Cfrac%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D%20%5C%5C%20%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D%5Ccdot%5Cfrac%7B%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D-%5Cfrac%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D%5Ccdot%5Cfrac%7B%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%20%5C%5C%20%5Cfrac%7B%282%2B%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29-%282-%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%20%5Cend%7Bgathered%7D)
We can now apply the distributive property for the both the numerator and denominator. We can see also that the denominator is the expansion of the difference of squares:
![\begin{gathered} \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2})^2-(\sqrt[]{2-\sqrt[]{3}}))^2} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})+(\sqrt[]{3}-2)\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{2^{}-(2-\sqrt[]{3})^{}} \\ \frac{\sqrt[]{2}\cdot(2+\sqrt[]{3})-\sqrt[]{2-\sqrt[]{3}}\cdot(2+\sqrt[]{3})+\sqrt[]{2}\cdot(\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}\cdot(\sqrt[]{3}-2)}{2-2+\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2+\sqrt[]{3}+\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}(-2-\sqrt[]{3}+\sqrt[]{3}-2)}{\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2\sqrt[]{3})+\sqrt[]{2-\sqrt[]{3}}(-4)}{\sqrt[]{3}} \\ 2\sqrt[]{2}-4\frac{\sqrt[]{2-\sqrt[]{3}}}{\sqrt[]{3}} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%282%2B%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29-%282-%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B%28%5Csqrt%5B%5D%7B2%7D%29%5E2-%28%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%29%5E2%7D%20%5C%5C%20%5Cfrac%7B%282%2B%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%2B%28%5Csqrt%5B%5D%7B3%7D-2%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B2%5E%7B%7D-%282-%5Csqrt%5B%5D%7B3%7D%29%5E%7B%7D%7D%20%5C%5C%20%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%5Ccdot%282%2B%5Csqrt%5B%5D%7B3%7D%29-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%5Ccdot%282%2B%5Csqrt%5B%5D%7B3%7D%29%2B%5Csqrt%5B%5D%7B2%7D%5Ccdot%28%5Csqrt%5B%5D%7B3%7D-2%29%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%5Ccdot%28%5Csqrt%5B%5D%7B3%7D-2%29%7D%7B2-2%2B%5Csqrt%5B%5D%7B3%7D%7D%20%5C%5C%20%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%282%2B%5Csqrt%5B%5D%7B3%7D%2B%5Csqrt%5B%5D%7B3%7D-2%29%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%28-2-%5Csqrt%5B%5D%7B3%7D%2B%5Csqrt%5B%5D%7B3%7D-2%29%7D%7B%5Csqrt%5B%5D%7B3%7D%7D%20%5C%5C%20%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%282%5Csqrt%5B%5D%7B3%7D%29%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%28-4%29%7D%7B%5Csqrt%5B%5D%7B3%7D%7D%20%5C%5C%202%5Csqrt%5B%5D%7B2%7D-4%5Cfrac%7B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D%7B%5Csqrt%5B%5D%7B3%7D%7D%20%5Cend%7Bgathered%7D)
We then can continue rearranging this as:
Answer:
2000 ml
Step-by-step explanation:
Given: Sarai pours all the liquid from a full small beaker into a larger beaker.
The liquid fills the large beaker to 15% of its capacity.
The small beaker holds 300 ml.
Lets assume capacity of large beaker to hold be "x".
As given, Sarai pours all the liquid from a full small beaker into a larger beaker
∴ 
⇒ 
Dividing both side by 0.15
⇒
∴ 
Hence, the large beaker can hold 2000 ml of liquid.